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nignag [31]
3 years ago
6

WILL GIVE BRAINLIEST

Mathematics
1 answer:
Virty [35]3 years ago
6 0
You need to find circumference, so you would multiply the diameter by pi. So your answer is 212pi feet or 666.02 feet
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At the beginning of a basketball season, the Warriors won 13 games and lost 5. If this rate continues, how many games will they
iragen [17]

Answer: 65 games

Step-by-step explanation:

total = 13 + 5 = 18

90 is 5x of 18

wins = 13*5 = 65 wins

8 0
3 years ago
A= 5,000 (1+.002*10)
Aneli [31]
I think The answer is 5100
3 0
2 years ago
2^n=8^20. Solve for n
damaskus [11]

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In a volleyball game, a player on one team spikes the ball over the net when the ball is 10 feet above the court. The spike driv
Fynjy0 [20]

Answer:

4.75 seconds

Step-by-step explanation:

Initial height of the ball from the ground = 10 feet

Upward initial velocity given = 55 feet per second

Value of g ( acceleration due to gravity) = 32.2 feet per s²

Motion of the ball:

The ball first goes vertically upwards, gravity decelerates the body and it momentarily comes to rest at a point in its upward trajectory, which is the point of maximum height. From this point, to the ground, the ball behaves as a freely dropped body.

Till the ball reaches its maximum height:

u = + 55

v = 0 ( final velocity is zero)

a = - 32.2 (since it is deceleration)

we know that <em>v = u + at </em>

⇒    0 = 55 - 32.2t

⇒  t = 1.7 s

Also , we have <em>s = ut + (1/2)at²</em>

Here, s is the maximum height from the point where ball is thrown

So,     s = 55(1.7) - (0.5)(32.2)(1.7)(1.7)

⇒ s = 140 feet

So at a height of 140 feet + 10 feet (initial height) = 150 feet, the ball acts as a freely dropped body.

Here,      u = 0

               a = +32.2

               s= 150

<em>s = ut + (1/2)at²</em>

⇒  150 = 0.5 ( 32.2) (t²)

⇒  t² = 300/32.2 = 9.31

⇒ t = 3.05 sec

So total time = 1.7 + 3.05 = 4.75 seconds

8 0
3 years ago
Can somebody pls help me on this
sdas [7]
Box 1:0,3,6,9,12, Box 2: 0,1,2, 14. Box3:1,9,13,18, box4:4,5,7hope this helps
4 0
2 years ago
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