1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MAVERICK [17]
3 years ago
6

Why is it important to know which category of microorganism has caused an infection?

Chemistry
2 answers:
patriot [66]3 years ago
7 0
Ima say a cause it sounds smart realistically
Gnoma [55]3 years ago
4 0

Answer:

A

Explanation:

You might be interested in
1. What is the equation for Boyle's Law?.
Sveta_85 [38]

Answer: 1. P1V1 = P2V2

2. P stands for pressure

3. Units for Pressure are atm and Pa

4. V stands for volume

5. Units for volume is in mL

Explanation: Boyle's Law is a gas law that states the relationship between pressure and volume of a gas.

8 0
3 years ago
Read 2 more answers
Elements in the periodic are listed according to
sammy [17]

Answer:

the raising atomic number

Explanation:

Elements are listed on the periodic table according to their atomic number.

6 0
3 years ago
An astronomer studying planets outside our solar system has analyzed the atmospheres of four planets. Which of these planets’ at
Nata [24]

Answer: Planet A: 76% Nitrogen, 23% Oxygen, 1% Other

Explanation: Hope this helps!

3 0
3 years ago
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

8 0
3 years ago
Decide whether the compound is ionic or molecular, if you can.
mestny [16]

Answer:

Molecular solid

Explanation:

A molecular solid has a low melting point, they are soft and do not conduct electricity.

We have been told in the question that the solid does not really dissolve in water and it's solution does not improve the electrical conductivity of water. Hence, it must be a molecular solid.

7 0
3 years ago
Other questions:
  • What is the mass of 2.15 liters of N2 gas at STP?
    12·1 answer
  • Sand and salt are poured into a single beaker. the result is a mixture because
    7·1 answer
  • The labeled images each represent the wave patterns found in the electromagnetic wave spectrum. Which image is correctly labeled
    11·2 answers
  • Select the correct answer. _____enable long-term resistance to infections that have been present in the body before. A. Monocyte
    5·1 answer
  • A 0.00100 moles sample of ca(oh)2 requires 25.00 ml of aqueous hcl for neutralization. how many moles of acid are contained in t
    15·1 answer
  • When a person uses an iron to remove the wrinkles from a shirt why does the heat travel from iron to the shirt?
    9·1 answer
  • The distance between the earth and the sun is 90.0 million miles . calculate this distance in meters up to three significant dig
    15·1 answer
  • The pKa of an acid depends partly on its environment. Predict the effect of each of the following environmental changes on the p
    15·1 answer
  • A gradual change over time in a species that enables the species to better survive in its environment is known as a(n)
    8·2 answers
  • A 50.0 ml beaker contains 680. g mercury what is the density of mercury
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!