Answer: ability to undergo a chemical reaction
Explanation:
Answer:
1. ![\rho=8.06g/cm^3](https://tex.z-dn.net/?f=%5Crho%3D8.06g%2Fcm%5E3)
2. ![H=10cm](https://tex.z-dn.net/?f=H%3D10cm)
Explanation:
Hello,
1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:
![V=21.4mL-18.3mL=3.1mL](https://tex.z-dn.net/?f=V%3D21.4mL-18.3mL%3D3.1mL)
Thus, the density turns out:
![\rho=\frac{m}{V}=\frac{25g}{3.1cm^3} \\\\\rho=8.06g/cm^3](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%7Bm%7D%7BV%7D%3D%5Cfrac%7B25g%7D%7B3.1cm%5E3%7D%20%20%5C%5C%5C%5C%5Crho%3D8.06g%2Fcm%5E3)
2. In this case, given the density and mass of aluminum we can compute its volume as follows:
![V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bm%7D%7B%5Crho%7D%3D%5Cfrac%7B1080g%7D%7B2.7g%2Fcm%5E3%7D%3D400cm%5E3)
Moreover, as the volume is also defined in terms of width, height and length:
![V=W*H*L](https://tex.z-dn.net/?f=V%3DW%2AH%2AL)
The height is computed to be:
![H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm](https://tex.z-dn.net/?f=H%3D%5Cfrac%7BV%7D%7BL%2AW%7D%3D%5Cfrac%7B400cm%5E3%7D%7B5cm%2A8cm%7D%5C%5C%20%5C%5CH%3D10cm)
Best regards.
Answer:
41.67 mol
Explanation:
1 Litre of water = 1000g
Mole = mass / molar mass
Mass of 1 L of water = 1000 g
Molar mass of water (H2O) :
(H = 1, O = 16)
H2O = (1 * 2) + 16 = (2 + 16) = 18g/mol
Amount of water consumed = (3/4) of 1 litre
= (3/4) * 1000g
= 750g
Therefore mass of water consumed = 750g
Mole = 750g / 18g/mol
Mole of water consumed = 41.6666
= 41.67 mol
Answer:
Electrical force can pull and push
Explanation:
132 grams x (1 mol / 44 grams) = 3 moles
<span>3 moles X (22.4 L/ 1 mol) = 67.2 </span><span>L</span>