<span>Step 1: find number of moles of Mg(divide 4.03 by its molor mass)
step 2:find number of moles in O2
step 3: remember STP is 22.4 L = 1 mole</span>
step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L
answer is 1860 mL
Answer:
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Answer:
The pH of the solution is 1.38.
Explanation:
Mass of HCl = 614 mg = 0.614 g
Moles of HCl = 
Concentration of HCl :

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
![[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M](https://tex.z-dn.net/?f=%5BHCl%5D%3D%5Cfrac%7B0.01682%20mol%7D%7B0.4%20L%7D%3D0.04205%20M)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
of hydronium ions.
![[H_3O^+]=0.04205 M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D0.04205%20M)
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pH=-\log [0.04205 M]=1.38](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5B0.04205%20M%5D%3D1.38%20)
The pH of the solution is 1.38.
<h3><u>Answer;</u></h3>
= 1.615 moles
<h3><u>Explanation</u>;</h3>
The molar mass of NO2
= 46.01 g/mol
The mass of NO2 given is 74.3 g
Number moles = mass/ molar mass
= 74.3 g/ 46.01 g/mol
= 1.615 moles