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irina1246 [14]
3 years ago
7

What is the name of the compound (NH4)2SO4

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0
The answer is Ammonium sulfate
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Consider this reaction. What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP? 1860 mL 2880 m
charle [14.2K]
<span>Step 1: find number of moles of Mg(divide 4.03 by its molor mass)
step 2:find number of moles in O2
step 3: remember STP is 22.4 L = 1 mole</span>
step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L
answer is 1860 mL
4 0
3 years ago
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Los neutrones tienen carga eléctrica———-y masa de ——una
3241004551 [841]

Answer:

thanks for your points

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6 0
2 years ago
A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol
tatuchka [14]

Answer:

The pH of the solution is 1.38.

Explanation:

Mass of HCl = 614 mg = 0.614 g

Moles of HCl = \frac{0.614 g}{36.5 g/ mol}=0.01682 mol

Concentration of HCl :

Concentration =\frac{Moles}{\text{Volume of solution in L}}

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.

[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M

HCl(s)+H_2O(l)\rightarrow H_3O^+(aq)+Cl^-(aq)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.

Then 0.04205 mol/L of HCl will give:

1\times 0.04205 M =0.04205 mol/L of hydronium ions.

[H_3O^+]=0.04205 M

pH=-\log [H_3O^+]

pH=-\log [0.04205 M]=1.38

The pH of the solution is 1.38.

7 0
3 years ago
How many moles of no2 are equivalent to 74.3g of no2
AfilCa [17]
<h3><u>Answer;</u></h3>

= 1.615 moles

<h3><u>Explanation</u>;</h3>

The molar mass of NO2

 = 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

                        = 74.3 g/ 46.01 g/mol

                       = 1.615 moles

6 0
2 years ago
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Food contains a sugar called , which is broken down in a process called cellular . This process uses to break down food molecule
melisa1 [442]

Answer:

glucose

respiration

oxygen

Explanation:

4 0
3 years ago
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