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irina1246 [14]
3 years ago
7

What is the name of the compound (NH4)2SO4

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0
The answer is Ammonium sulfate
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Question 9 Multiple Choice Worth 4 points)
Rufina [12.5K]

Answer:

A

Explanation:

Would you base your career options using science?

Would you base your moral behavior on science? Science is notorious for not being able to answer moral questions.

Would you base the "meaning of life" on science? The meaning of life is hardly a question that the periodic table could answer.

The only option left is plant growth which science could answer.

4 0
3 years ago
Read 2 more answers
What is the ph of a solution with [h3o+] = 1 × 10-9 m?
FrozenT [24]
PH scale is used to determine how acidic, basic or neutral a solution is
pH can be calculated using the H₃O⁺
ph can be calculated as follows
pH = - log[ H₃O⁺]
[H₃O⁺] = 1 x 10⁻⁹
pH = - log [1 x 10⁻⁹]
 pH = 9
pH of solution is 9
7 0
3 years ago
Determine the equilibrium constant, Kp, for the following reaction, by using the two reference equations below: 2 NO(g) + O2(g)
klio [65]

Answer:

Kp=3.07x10^6

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}

N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}

Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):

2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2

Consequently, the equilibrium constant is computed as:

Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6

Best regards.

8 0
3 years ago
In the following reaction, C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O,
shepuryov [24]
The answer is 27.92g . working is shown in the picture above.

3 0
3 years ago
How many moles do you have in 37.3 g of Co(CrO4)3​
shutvik [7]

Answer:

0.0917 mol Co(CrO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

37.3 g Co(CrO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Co - 58.93 g/mol

Molar Mass of Cr - 52.00 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol

<u>Step 3: Convert</u>

<u />37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} ) = 0.091662 mol Co(CrO₄)₃

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃

8 0
3 years ago
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