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hichkok12 [17]
2 years ago
10

PLEASE HELP ME TIMED TEST!!!

Physics
2 answers:
Dmitry [639]2 years ago
8 0

Explanation:

\boxed{\sf{K.E = \dfrac{1}{2} \times m \times v^2}}

  • Here, K . E or Kinetic Energy is given as 14 J
  • Here, mass is 17 kg

Let's Do!

\boxed{\sf{14 = \dfrac{1}{2} \times 17 \times v^2}}

\boxed{\sf{\dfrac{14 \times 2}{17} = v^2}}

\boxed{\sf{ \sqrt{\dfrac{14 \times 2}{17}}= v}}

So, 1.283 m/s is the required answer.

malfutka [58]2 years ago
7 0

Answer:

56

Explanation:

I just want the points to be completely honest with you.  

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A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
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Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

Solve for ω₂

460 = 295 + 0.5ω₂

ω₂ = 330rpm

a)

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

b)

ω₂ = ω₁ + αt

0 = 590 +(-520)t

520t = 590

solve for t

t = 590 / 520

t = 1.13min

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X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0
3 years ago
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