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valkas [14]
3 years ago
6

A roller coaster is released from the top of a track that is 57 m high. Find the roller coaster speed when it reaches ground lev

el.
Physics
1 answer:
Art [367]3 years ago
7 0

Hi there!

Assuming the track is frictionless:

E_i = E_f\\\\PE = KE\\\\mgh = \frac{1}{2}mv^2

Cancel out the masses and rearrange to solve for velocity:

gh = \frac{1}{2}v^{2}\\\\v = \sqrt{2gh}\\\\

Plug in the given height and let g = 9.8 m/s²:

v = \sqrt{2(9.8)(57)} = \boxed{33.42 m/s}

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Glad I could help!

Call me if ya need anything!

:)

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