Helppppppppppppp pleaseeeeeeee

Express 11 out of 25 as a percentage

Alexeev081 [22]

Answer:

44%

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the value of y if B is between A and C, AB is 2y, BC is 6y, and AC is 48.

Len [333]

Answer:

7. C. 6

8. H. √34

9. A. (1, 3.5)

10. J. 10

Step-by-step explanation:

7. AB = 2y, BC = 6y, AC = 48

AB + BC = AC (segment addition theorem)

Substitute the above values into the equation

2y + 6y = 48

Solve for y

8y = 48

Divide both sides by 8

8y/8 = 48/8

y = 6

8. Distance between P(2, 8) and Q(5, 3):

$PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$P(2, 8) = (x_1, y_1)$

$Q(5, 3) = (x_2, y_2)$

$PQ = \sqrt{(5 - 2)^2 + (3 - 8)^2}$

$PQ = \sqrt{(3)^2 + (-5)^2}$

$PQ = \sqrt{9 + 25}$

$PQ = \sqrt{34}$

9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $L(8, 5) = (x_1, y_1)$

$B(-6, 2) = (x_2, y_2)$

Thus:

$M(\frac{8 + (-6)}{2}, \frac{5 + 2}{2})$

$M(\frac{2}{2}, \frac{7}{2})$

$M(1, 3.5)$

10. M = -10, N = -20

Distance between M and N, MN = |-20 - (-10)|

= |-20 + 10| = |-10|

MN = 10

5 0

4 years ago

A cylindrical bucket and spherical storage container are shown. The bucket has a radius of 6 inches and a height of 15 inches, a

inysia [295]

Answer:

To know if Nicholas is correct

4(540π) inches³ ≥ 2304π inches³

Unfortunately, 2160π inches³ is less than 2304π inches³. This means Nicholas is absolutely wrong .4 times the volume of the cylindrical bucket is less than the volume of the spherical tank.

Step-by-step explanation:

The question wants you to look for the volume of the cylindrical bucket and the spherical bucket and know if 4 times the volume of the cylindrical bucket will fill the spherical tank.

volume of a cylinder = πr²h

where

r = 6 inches

h = 15 inches

volume of the cylinder bucket = πr²h

volume of the cylinder bucket= π × 6² × 15

volume of the cylinder bucket = π × 36 × 15

volume of the cylinder bucket = 540π inches³

volume of the spherical storage container

volume = 4/3πr³

r = 24/2 = 12 inches

volume = 4/3 × π × 12³

volume = 4/3 × π × 1728

volume = 6912π/3

volume = 2304π inches³

To know if Nicholas is correct 4(540π) inches³ ≥ 2304π inches³

Unfortunately, 2160π inches³ is less than 2304π inches³. This means Nicholas is absolutely wrong .4 times the volume of the cylindrical bucket is less than the volume of the spherical tank.

8 0

4 years ago

An expression is shown. 800 / 80 What is the value of the expression?

blondinia [14]

$\frac{800}{80} = \frac{80*10}{80*1} = 10$

7 0

3 years ago

You are laying a concrete border around a circular pond ...The pond is 7 meters in diameter and is surrounded by a path 2 metres

nasty-shy [4]

Answer:

300 bags of 20 kg of premixed are required.

Step-by-step explanation:

Given:

diameter of pond 'd'= 7 m (given)

radius of inner border of pond 'r'= d/2= 7/2 m

The radius of outer circular border 'R'= r+2= 7/2+2= 11/2m

Area of concrete border around the circular pond= area of outer circle- area of inner circle

So, $\pi\times R^2-\pi\times r^2= \pi\times (R^2-r^2)$

=> 22/7 x ((11/2)²-(7/2)²)

=> 22/7 x (121/4-49/4)

=> $\frac{22}{7} \times \frac{72}{4}$

=> 56.57 m²

volume of concrete needed= area x height= 56.57 x 0.05= 2.8285 cubic meter

Since 1 cube meter requires 106 x 20 kg bags,

2.8285 cubic meters require bags= 2.8285x106x20 kg

20 kg bags of premixed concrete required= 2.8285x106x20/20

=> 2.8285x106

=> 299.821 or 300 approximately

5 0

4 years ago