The answer is true. It tells me I have to have 20 characters.
Answer:
86.6, 45°
Explanation:
The diagram explains better.
Using vector component method:
We find the x and y components of the vectors :
For the first:
A = -50cos(0)i + 50sin(0)j
A = -50i
For the second:
B = -50cos(60)i + 50sin(60)j
B = -25i + 43.3j
The resultant vector is :
R = A + B
R = -50i - 25i + 43.3j
R = -75i + 43.3j
The magnitude is:
R = [(-75)² + (43.3)²]^½
R = 86.6m
The angle is
tanθ = (50/50) = 1
θ = 45°
(5 bulbs) x (25 watt/bulb) x (6 hour/day) x (30 day/month) =
(5 x 25 x 6 x 30) watt-hour/month =
22,500 watt-hour/month .
The most common unit of electrical energy used for billing purposes
is the 'kilowatt-hour' = 1,000 watt-hours .
22,500 watt-hour/month = <em>22.5 kWh/month</em>.
(22.5 kWh/month) x (1.50 Rs/kWh) = <em>33.75 Rs / month
</em>
Weight of the bus= mass x acceleration due to gravity = 1021x9.8 = 10005.8 N. Hope it helps.
Answer:
1.11×10¹⁹ electrons
Explanation:
The formula for electric energy is given as,
E = QV ................. Equation 1
Where E = Electric Energy, Q = charge, V = Voltage.
Make Q the subject of the equation
Q = E/V............... Equation 2
Given: E = 8 W, V = 4.5 V.
Substitute into equation 2
Q = 8/4.5
Q = 1.778 C
using,
n = Q/e............ Equation 3
Where n = number of electron, e = Charge of one electron.
Given: e = 1.6×10⁻¹⁹ C
Substitute into equation 3
n = 1.778/1.6×10⁻¹⁹
n = 1.11×10¹⁹ electrons
