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IrinaVladis [17]
2 years ago
7

A hunter stood at about 60 m away from a tree. He used the bow to release the arrow in order to shoot a coconut held by a monkey

in the tree. The coconut was at a height of 25 m from the ground. The hunter aimed directly at the coconut and the arrow left the bow at 45 m/s making an angle of 20 degree to the horizontal. At the moment thebhunter released the arrow, the monkey dropped the coconut such that it falls vertically from rest. Neglect air resistance and the arrow's size. What is the time taken for the arrow to hit the coconut?​
Physics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

Answer:

v = u + at (upward)\\ 0 = 45 \sin(20)  - 9.81t \\ t = 1.56s

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If you weighed 100 lb on Earth, what would you weigh at the upper atmosphere of Jupiter? For reference, Jupiter has a mass that
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Answer:

The answer to the question is

A 100 lb person would weigh 300.33 lbf at the upper atmosphere of Jupiter

Explanation:

To solve the question we note that

Mass of object = 100 lb =‪ 45.35924‬ kg

Mass of Jupiter = 300×Mass of Earth = 300×5.972 × 10²⁴ kg =1.7916×10²⁷ kg

Radius of Jupiter = 10× Radius of Earth = 10×6,371 km = 63710 km

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Plugging in the values we get

F_G = \frac{6.67408*10^{-11}*45.35924*1.7916*10^{27}}{63710^2} = 1335.93 N

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7 0
2 years ago
Corey runs a 100-meter race. 7 seconds after the race started Corey is 45 meters from the starting line and reaches his max spee
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Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
  • d (z) = 45 m + 7 \frac{m}{s} * z
  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

v=\frac{distance}{time}

The distance between the 80 meters and the 45 meters is:

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and the time it took to reach the 80 meter will be:

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So, Corey's max speed is

v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

<h3>What is Corey's distance from the starting line</h3>

At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

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