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IrinaVladis [17]
3 years ago
7

A hunter stood at about 60 m away from a tree. He used the bow to release the arrow in order to shoot a coconut held by a monkey

in the tree. The coconut was at a height of 25 m from the ground. The hunter aimed directly at the coconut and the arrow left the bow at 45 m/s making an angle of 20 degree to the horizontal. At the moment thebhunter released the arrow, the monkey dropped the coconut such that it falls vertically from rest. Neglect air resistance and the arrow's size. What is the time taken for the arrow to hit the coconut?​
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

v = u + at (upward)\\ 0 = 45 \sin(20)  - 9.81t \\ t = 1.56s

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A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?
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Answer:

The answer to your question is:

Explanation:

Data

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v = ?

Formula

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Clear v from the equation

v = √2ke/m

Substitution

v = √2(41.7)/4.33

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Light of wavelength 597 nm falls on a double slit, and the first bright fringe of the interference pattern is seen at an angle o
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Answer:

2.2 µm

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For each of the following pairs of gas properties, describe the relationship between the properties, describe a simple system th
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Answer:

For  each pair of properties of a gas, the relationships are (see the explanation for the description of the systems):

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  2. (b) Pressure and temperature: They have a directly proportional relationship.
  3. (c) Volume and temperature: They relationship is directly proportional.
  4. (d) Number of gas particles and pressure: The relationship is directly proportional between them.

Explanation:

1. Volume and pressure (temperature and amount of particles constant):

They have an inversely proportional relationship, because <em>if volume is reduced, the pressure increases, or if the volume increases, the pressure decreases</em>.

A simple system could be one similar to the one used by Boyle to test this relationship:

  • Seal the short extreme of a translucent J tube. It could be glass or plastic.
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  • Using a syringe, and a flexible small tube,inject a determined volume of air in the bottom in a way that the bubble is trapped in the seal side of the J tube.
  • Then if more water is added to the tube, it will increase the pressure (from the pressure definition is possible to in the trapped air, and is possible to measure the compression of the air bubble. The same is possible if using the syringe, and the flexible tube, some water is removed, and the increasing of volume could be observed.

2. Pressure and temperature (volume and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure would increase, also</em>.

A simple system to show this is two cans of soda.

  • The can is rigid, so the volume is always constant, and the amount of gas inside the soda is the same.
  • Put one can under the sun, and the other in the cooler.
  • After a while, take it out the can in the cooler, and open both cans.
  • The one that was under the sun will "explode", in other words, it will liberate a lot of foam of gas and soda, meaning that the pressure inside the can was high.
  • The one that was in te cooler, won't liberate any foam, meaning that the pressure was low.

3. Volume and temperature (pressure and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure will increase, also</em>.

A simple system to show this is a party balloon.

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  • Now is possible to use some heat source, for example as a hair dryer to increase the temperature of the balloon and its contents. The size of the balloon will increase. Then using water is possible to cool it down and watch how its size decreases.

4. Number of gas particles and pressure (volume and temperature of gas remains constant)

They have a directly proportional relationship, because <em>if the amount of gas particles is reduced, the pressure decreases, or if quantity of gas particles increases, the pressure will increase, also</em>.

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  • Also, is possible to open the valve, to allow some air to escape, then use the gauge to observe how the pressure decreases.

7 0
3 years ago
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