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Mice21 [21]
2 years ago
14

Analyze if the frequency of a sound wave increases what happnes to the wavelength

Physics
2 answers:
nikklg [1K]2 years ago
4 0

Answer:

it's either a b c or do I swear

DIA [1.3K]2 years ago
4 0
Can you mark me brainliest please I’m trying to rank up!:)
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A fly ball was caught by the third baseman and thrown to first base at a speed
Degger [83]

Answer:

im smart pls mark brainliest

Explanation:

12 seconds

6 0
3 years ago
Derive an equation of motion s=ut+1/2at2 for an object moving in straight line​
igor_vitrenko [27]

Answer:

sut12at2

Explanation:

sorry just need points

5 0
3 years ago
On a certain map, every 3 cm represents 6 km on earth surface. Which ratio represents the scale of the map, which shows how the
damaskus [11]

Answer:

1 : 2 cm/km  or \frac{1}{2} \, \frac{cm}{km}

One cm represents 2 km.

Explanation:

If 3 cm represents 6 km on the earth, the ratio to consider is: 3 : 6  cm/km which is the same as:  

1 : 2 cm/km  or \frac{1}{2} \, \frac{cm}{km}

One cm represents 2 km.

4 0
3 years ago
How could you determine the injuries or ill person in a secondary assessment?
lana66690 [7]

Answer:

just in internet tho

6 0
2 years ago
Read 2 more answers
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
rusak2 [61]

I'll bite:

-- Since the sled's mass is 'm', its weight is 'mg'.

-- Since the coefficient of kinetic friction is μk, the force acting opposite to the direction it's sliding is    (μk) times (mg) .

-- If the pulling force is constant 'F', then the horizontal forces on the sled
are 'F' forward and (μk · mg) backwards.

-- The net force on the sled is  (F - μk·mg).
(I regret the visual appearance that's beginning to emerge,
but let's forge onward.)

-- The sled's horizontal acceleration is  (net force) / (mass) = (F - μk·mg) / m.
This could be simplified, but let's not just yet.

-- Starting from rest, the sled moves a distance 's' during time 't'.
We know that  s = 1/2 a t² , and we know what 'a' is.  So we can write

           s = (1/2 t²)  (F - μk·mg) / m    .

Now we have the distance, and the constant force.
The total work is (Force x distance), and the power is (Work / time).
Let's put it together and see how ugly it becomes.  Maybe THEN
it can be simplified.

Work = (Force x distance) =  F x  (1/2 t²)  (F - μk·mg) / m
 
Power = (Work / time) =    <em>F (t/2) (F - μk·mg) / m </em>

Unless I can come up with something a lot simpler, that's the answer.


To simplify and beautify, make the partial fractions out of the
2nd parentheses:
                                   <em> F (t/2) (F/m - μk·m)</em>

I think that's about as far as you can go.  I tried some other presentations,
and didn't find anything that's much simpler.

Five points,ehhh ?


4 0
2 years ago
Read 2 more answers
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