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olga_2 [115]
3 years ago
9

Jordan Gracia 32 sub and 5 videos

Engineering
2 answers:
xz_007 [3.2K]3 years ago
5 0

Do you want me to sub? I'll sub if you give me brainliest

Viktor [21]3 years ago
5 0
I don't give a flying
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The format_address function separates out parts of the address string into new strings: house_number and street_name, and return
gizmo_the_mogwai [7]

function format_address separates it into two strings :

house_number and

street_name

Explanation:

For example, “123 Main Street”, “1001 1st Ave”, or “55 North Center Drive”. Fill in the gaps to complete this function.

 # Declare variables

 house_number =''

 street_name =''

 # Separate the address string into parts

 spi = address_string.split()

 # Traverse through the address parts

 for ele in spi:

   # Determine if the address part is the

   # house number or part of the street name

   if ele.isdigit():

     house_number = ele

   else:

     street_name += ele

     street_name += ' '

 # Does anything else need to be done  

 # before returning the result?

 

 # Return the formatted string  

 return "house number {} on street named {}".format(house_number, street_name)

6 0
4 years ago
An engineer must design a rectangular box that has a volume of 9 m3 and that has a bottom whose length is twice its width. What
Jet001 [13]

Answer:

Length =3   Height = 2   and  Width = \frac{3}{2}

Explanation:

Given

Volume = 9m^3

Represent the height as h, the length as l and the width as w.

From the question:

Length = 2 * Width

l = 2w

Volume of a box is calculated as:

V = l*w*h

This gives:

V = 2w *w*h

V = 2w^2h

Substitute 9 for V

9 = 2w^2h

Make h the subject:

h = \frac{9}{2w^2}

The surface area is calculated as:

A = 2(lw + lh + hw)

Recall that: l = 2w

A = 2(2w*w + 2w*h + hw)

A = 2(2w^2 + 2wh + hw)

A = 2(2w^2 + 3wh)

A = 4w^2 + 6wh

Recall that: h = \frac{9}{2w^2}

So:

A = 4w^2 + 6w * \frac{9}{2w^2}

A = 4w^2 + 6* \frac{9}{2w}

A = 4w^2 + \frac{6* 9}{2w}

A = 4w^2 + \frac{3* 9}{w}

A = 4w^2 + \frac{27}{w}

To minimize the surface area, we have to differentiate with respect to w

A' = 8w - 27w^{-2}

Set A' to 0

0 = 8w - 27w^{-2}

Add 27w^{-2} to both sides

27w^{-2} = 8w

Multiply both sides by w^2

27w^{-2}*w^2 = 8w*w^2

27 = 8w^3

Make w^3 the subject

w^3 = \frac{27}{8}

Solve for w

w = \sqrt[3]{\frac{27}{8}}

w = \frac{3}{2}

Recall that : h = \frac{9}{2w^2}   and l = 2w

h = \frac{9}{2 * \frac{3}{2}^2}

h = \frac{9}{2 * \frac{9}{4}}

h = \frac{9}{\frac{9}{2}}

h = 9/\frac{9}{2}

h = 9*\frac{2}{9}

h= 2

l = 2w

l = 2 * \frac{3}{2}

l = 3

Hence, the dimension that minimizes the surface area is:

Length =3   Height = 2   and  Width = \frac{3}{2}

6 0
3 years ago
Refrigerant 134a at p1 = 30 lbf/in2, T1 = 40oF enters a compressor operating at steady state with a mass flow rate of 200 lb/h a
Mazyrski [523]

Answer:

a) \mathbf{Q_c = -3730.8684 \ Btu/hr}

b) \mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}

Explanation:

From the properties of Super-heated Refrigerant 134a Vapor at T_1 = 40^0 F, P_1 = 30  \ lbf/in^2 ; we obtain the following properties for specific enthalpy and specific entropy.

So; specific enthalpy h_1 = 109.12 \ Btu/lb

specific entropy s_1 = 0.2315 \ Btu/lb.^0R

Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at P_2 = 160 \ lbf/in^2 ; we obtain the following properties:

h_2  = 115.91 \ Btu/lb\\\\ s_2 = 0.2157 \ Btu/lb.^0R

Given that the power input to the compressor is 2 hp;

Then converting to  Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr

2 hp = 2 × 2544.4342 Btu/hr

2 hp = 5088.8684 Btu/hr

The steady state energy for a compressor can be expressed by the formula:

0 = Q_c -W_c+m((h_1-h_e) + \dfrac{v_i^2-v_e^2}{2}+g(\bar \omega_i - \bar \omega_e)

By neglecting kinetic and potential energy effects; we have:

0 = Q_c -W_c+m(h_1-h_2) \\ \\ Q_c = -W_c+m(h_2-h_1)

Q_c = -5088.8684 \ Btu/hr +200 \ lb/hr( 115.91 -109.12) Btu/lb  \\ \\

\mathbf{Q_c = -3730.8684 \ Btu/hr}

b)  To determine the entropy generation; we employ the formula:

\dfrac{dS}{dt} =\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c

In a steady state condition \dfrac{dS}{dt} =0

Hence;

0=\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c

\sigma _c = m( s_1 -s_2)  - \dfrac{Qc}{T}

\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R  - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]

\sigma _c = [(-3.16 ) \ Btu/hr .^0R  + (7.4667 ) Btu/hr ^0R}]

\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}

5 0
4 years ago
failure to yield the right-of-way to another vehicle or pedestrian is the primary Collision factor in about 20% of fatal and inj
laila [671]

You could just create a turn on green arrow. Have a button for pedestrians. The only way for them to turn is if they have a green arrow and the green arrow will only appear when pedestrians are stopped or finished walking and all cars are clear or fully stopped

8 0
4 years ago
Why did my dad leave me yesterday like whatd i do?
Vsevolod [243]

Answer:

hmm i would try calling him. ask your mom or other adults where he is!

Explanation:

hope you get help soon!

4 0
3 years ago
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