Explanation:
Styrene is a vinyl monomer in which there is a carbon carbon double bond.
The polymerization of the styrene, which is initiated by using a free radical which reacts with the styrene and the compound thus forms react again and again to form polystyrene (PS).
The equation is shown below as:
⇒ ![\begin{matrix}&C_6H_5 \\&|\\ -[-H_2C & -CH-]-_n\end{matrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bmatrix%7D%26C_6H_5%20%5C%5C%26%7C%5C%5C%20-%5B-H_2C%20%26%20-CH-%5D-_n%5Cend%7Bmatrix%7D)
It is important because now a days we all need help from engineers
Answer:
D=41.48 ft

Explanation:
Given that
y=0.5 x²
Vx= 2 t
We know that

At t= 0 ,x=0

At t= 3 s

![x=[t^2\left\right ]_0^3](https://tex.z-dn.net/?f=x%3D%5Bt%5E2%5Cleft%5Cright%20%5D_0%5E3)
x= 9 ft
When x= 9 ft then
y= 0.5 x 9² ft
y= 40.5 ft
So distance from origin is
x= 9 ft ,y= 40.5 ft

D=41.48 ft

Vx= 2 t

At t= 3 s , x= 9 ft
y=0.5 x²

y=0.5 x²


Given that








Answer:
B. Acid rain.
C. Photochemical smog.
Explanation:
Oxides of nitrogen contribute to the formation of photochemical smog and acid rain. Photochemical smog is a type of smog produced when ultraviolet light from the sun reacts with nitrogen oxides in the atmosphere while on the other hand, when nitrogen oxide react with the water vapor in the atmosphere forming nitric acid which falls on the earth surface with the help of precipitation.
Answer:
work is 50 kj
Explanation:
Given data
heat (Q) = 50 kj
To find out
work input for the compression stroke per kilogram of air
Solution
we will apply here "first law of thermodynamics" i.e.
The First Law of Thermodynamics states that heat is a form of energy, subject to the principle of conservation of energy, that heat energy cannot be created or destroyed. It can be transferred from one location to another location. i.e.
ΔU = Q – W ................1
here ΔU is change in internal energy, Q is heat and W is work done
here U = 0 because air compressor the compression takes place at a constant internal energy in question
so that by equation 1
Q = W
and Q = 50
so work will be 50 kj