Answer:
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Answer:
Aluminum cross sectional area = 1.99 * 10^-5 mm^2
Steel cross sectional area = 9.95* 10^-6 mm^2
Explanation:
Given data:
Tensile strength of Grunerite = 3.5 * 10^2 kg/mm^2 = 3.5 * 10^-4 kg/<em>u</em>m^2
Tensile strength of Aluminum = 2.5 × 10^4 lb/in2 = 2.5 × 10^4 * 703.07 kg/m^2
Tensile strength of Steel number 5137 = 5.0 × 10^4 lb/in2 = 5.0 × 10^4*703.07 kg/m^2
<u>Calculating the cross sectional area of the wires of aluminum and steel No5137</u>
first we will determine the cross sectional area of the aluminum wire ( A ) by equating tensile strength of aluminum with the tensile strength
of Grunerite
(2.5 × 10^4 * 703.07) * A = 3.5 * 10^-4 kg
Hence ; A = 1.99 * 10^-5 mm^2
Next we calculate the cross sectional area of steel
5.0 × 10^4*703.07 kg/m^2 * A" = 3.5 * 10^-4 kg
Hence ; A" = 9.95* 10^-6 mm^2
Answer:
Explanation:
A continuous fiber-reinforced composite is to be produced by dispersing 60 vol% carbon fibers in a polycarbonate matrix. if the stress in the polycarbonate matrix when the carbon fibers fail is 45 mpa, the longitudinal elastic modulus of the composite using rule of mixture
Given Information:
Capacitor 1 = C₁ = 100 μF
Capacitor 2 = C₂ = 300 μF
Voltage rating of capacitor 1 = 25 V
Voltage rating of capacitor 2 = 35 V
Supply voltage = Vs = 100 V
Required Information:
Which capacitor will be damaged = ?
Answer:
Capacitor 1 will get damaged
Explanation:
The given two capacitors are connected in series, the equivalent capacitance will be
The voltage across the capacitor 1 is
Since the voltage rating of capacitor 1 is 25 volts, it will get damaged because 75 volts are much greater as compared to its voltage rating.
The voltage across the capacitor 2 is
Since the voltage rating of capacitor 2 is 35 volts, it will not get damaged because 25 volts are less as compared to its voltage rating.