Answer:
b) O₂
d) CH₄
Explanation:
In a chemical equation, the <u>reactants</u> are the substances that are written on the <u>left side</u>. The reactants react to produce the products. On the right side, the products are written.
The arrow => is used to separate the reactants from the products.
To the left of the arrow, you can see this written:
CH₄ + 2O₂
The plus sign + is used to separate each reactant.
In 2O₂ you can ignore the big 2 because it is a coefficient, which is written to balance the equation.
The reactants are CH₄ and O₂
A pure substance refers to an element or a compound that has no component of another compound or element. Pure substances are made of only one type of atom or molecule. Hydrogen gas and pure iron are examples of pure substances. Hydrogen consists of hydrogen atoms only while iron consists of only iron atoms. Mixing two pure substances results in a mixture. To separate the two, scientists use a method known as filtration. Mixtures can either be homogeneous or heterogeneous. The measure used to determine how pure a substance may be called purity. Besides hydrogen and iron, other pure substances include gold, diamonds, sugar, and baking soda.
<span>This type of salt is called a hydrated salt. This specific salt is called Cobalt (II) chloride hexahydrate. Hydrated salts is a salt has a number of water molecules associated with the ions in its crystalline structure.</span>
<h3>Al + O2 -> Al2O3</h3>
Balance it:
<h3>2Al + 3O2 -> 2Al2O3</h3><h3 />
So you need 2 Al and 3 O2 to make 2 Al2O3 (aluminum oxide).
I'm going to assume you have all the O2 you need.
Since 2 mols of Al is needed to make 2 mols of the product, it's a 1:1 ratio. You get as much aluminum oxide for as much aluminum you burn.
So 12.5 mols if there is not a lack of the O2.
Answer:
Explanation:
Hello!
In this case, since the reaction between sulfuric acid and aluminum hydroxide is:
Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:
Then, given the molarity, it is possible to obtain the milliliters as follows:
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