The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.
        
             
        
        
        
Answer:
Ribosome, Hexokinase, Glucose, CO2.
Ribosomes are proteins that sintetize the proteins in the cell, depending of the organism, the can size up to 30 nm. Hexokinase is an enzyme that measures approximately 50 kDa, and in its spatial conformation it sizes about 5 to 6 nm in diameter. Glucose is a molecule that sizes about 1 nm, and CO2 is another molecule that sizes 0.232 nm. 
 
        
             
        
        
        
The mole fraction of pentane in the vapor is 0.291
Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface. 
The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.
Using the formula for vapour pressure,
vapour pressure =  °
° ×
 ×  +
 +  °
° ×
 × 
vapour pressure = 151 ×  

 + 425 ×
 + 425 × 
240 = 151 - 151 + 425
 + 425
240 - 151 = -  151 + 425
 + 425 
89 = 274 
 =
 = 
0.291 = 
Therefore,  the mole fraction of pentane in the vapor is 0.291
Learn more about vapour pressure here;
brainly.com/question/25699778
#SPJ4
 
        
             
        
        
        
The freezing point depression of the solution or pure substance that is added with the solvent is calculated through the equation,
    
  ΔTf = Kfm
where ΔT is the freezing point depression, Kf is the constant for water given to be -1.86°C/m and m is the molality of the solution. 
Molality is calculated through the equation,
    
    m = number of moles solute/ kg of solvent
Calculation of molality is shown below.
    
   m = (21.5 g C6H12O6)(1 mol/180 g) / (0.255 kg)
     m = 0.468 molal
The freezing point depression is then,
    
   ΔTf = (-1.86°C/m)(0.468 m) = -0.87°C
<em>Answer: -0.87°C</em>