Ask question

Ask question

All categories

3 years ago

7

What would the final salt concentration be if instead of placing the dialysis bag in 4.0 L of distilled water for 12 h, you plac

ed the bag in 1.0 L of distilled water for 6.0 h and then in another 1.0 L of fresh distilled water for another 6.0 h

1 answer:

alexdok [17]3 years ago

4 0

Answer:chicken

Explanation:There are many types of chicken

You might be interested in

If a material contains three elements but not joined in a fixed proportion, it is a(an) A. mixture. B. compound. C. atom. D. non

BartSMP [9]

B. compound a material that contains three elements joined in a fixed proportion

7 0

4 years ago

Read 2 more answers

What is the number of moles in 500L of He

Volgvan

Answer:

20 moles

Explanation:

The important thing to realize here is that you're working under STP conditions, which implies that you can use the molar volume of a gas at STP to find how many moles of helium will occupy that volume.

4 0

4 years ago

Read 2 more answers

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago

In a cell, what is the function of the Cell Membrane?

joja [24]

The answer is C :

It controls the entry and exit of substances.

8 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST ! Where did the mass of the forest trees come from? What happens to that mass when the forest b

Oxana [17]

Answer:

it is a flat mass

Explanation:

Because it was used up.

3 0

3 years ago