All categories

3 years ago

How many ounces are in 2 pounds

Mathematics

1 answer:

Mamont248 [21]3 years ago

4 0

Answer:

1. 32 ounces

2. 3 pounds

Step-by-step explanation:

1. There are 16 ounces in a pound, so you multiply 2 by 16.

2. Divide 48 by 16.

You might be interested in

Mis Meyer's paid $3600 all together for the equipment, furniture and decorations for her restaurant. The equipment cost $500 mor

Tju [1.3M]

Answer:

The equipment will cost $1740.

Step-by-step explanation:

Let the Cost of equipment, furniture and decoration be x, y and z.

Now, According to question,

x + y + z = 3600 ...... (1) (cost of all items)

x = 500 + y (∵ equipment cost 500 more than furniture)

and y = 2z ( ∵ furniture twice as much as decoration)

so, z = y/2

Now substituting the value of x and z in eq (1)

$x + y + z = 3600$

$500 + y + y + \frac{y}{2} = 3600$

$2y + \frac{y}{2} = 3600 - 500$

$\frac{5y}{2} = 3100$

$y = \frac{3100\times 2}{5} = 1240$

So, the cost of furniture (y) = 1240

∴ Cost of equipment = y + 500 = 1240 + 500 = 1740

Therefore the cost of equipment was $1740.

3 0

3 years ago

12000 pennie s equal

Arlecino [84]

There are 100 pennies in a dollar. We can divide 12000 pennies by 100 to find out how much they are worth in dollars.

12000/100 = $120

8 0

3 years ago

Read 2 more answers

Find four consecutive integers with the sum of 54

Maksim231197 [3]

54/4 = 13.5

take the 2 whole numbers below 13.5 and the 2 whole numbers above 13.5

12 + 13 + 14 + 15 = 54

7 0

3 years ago

PLEASE HELP, ITS TIMED HURRY >>>>

tresset_1 [31]

Answer:2

Step-by-step explanation:

IM FAST RIGHT???

3 0

3 years ago

Read 2 more answers

Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 )left parenthesis, 0, comma

steposvetlana [31]

Answer:

$\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) $\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }$ .

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

$\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

8 0

3 years ago