Answer:
Explanation:
first, you calculate the amount of O2 in moles:
98.0 ÷ 32 = 3.0625
second, the ratio if O2/C3H8 is 5 so you need to calculate O2 in moles with that:
3.0625 ÷ 5 = 0.6125
third, the amount of CO2 in moles also can be calculate by the ratio of C3H8/CO2 which is 3
0.6125 × 3 = 1.8375
then multiply CO2 in moles by its molar mass which is 44 g/mol
1.8375 × 44 = 80.85g
Answer:
F. Universe
Explanation:
Universe and Galaxies are two different things.
Answer:
Percent yield = 89.1%
Explanation:
Based on the equation:
Cl₂ + 2KI → 2KCl + I₂
<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>
<em />
To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:
<em>Moles Cl₂:</em>
8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles
<em>Moles KI -Molar mass: 166.0028g/mol-</em>
25g * (1mol / 166.0028g) = 0.15 moles
Here, clarely, the KI is the limiting reactant
As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:
0.15 moles * (74.5513g / mol) =
11.2g KCl
Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100
<h3>Percent yield = 89.1%</h3>
