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jeka57 [31]
2 years ago
6

A gas sample occupies 2.1 L at a pressure of 101 kPa.

Chemistry
2 answers:
Georgia [21]2 years ago
7 0

Answer:

0.9L

Explanation:

Given parameters:

Initial volume = 2.1L

Initial pressure  = 101kPa

Final pressure  = 235kPa

Unknown:

Final volume  = ?

Solution:

The relationship is between pressure and volume. To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

        P₁V₁  = P₂V₂

P₁ is the initial pressure

V₁ is the initial volume

P₂ is the final pressure

V₂ is the final volume

 Now insert the parameters and solve;

        2.1 x 100 = 235 x V₂

            V₂ = 0.89L

Verizon [17]2 years ago
6 0

Answer:

D) 0.9 L

Explanation:

At constant temperature,

PV = Constant

so,

P1.V1 = P2. V2

101 × 2.1 = 235 × V2

V2 = 0.9 L

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The nutritional energy content (in Calories) present in 86g of broccoli with 6g of carbohydrates, 2.6g of protein, and 0.3g of f
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Answer:

37.1 calories.

Approximately, 37.1 = 40 calories.

Explanation:

So, without mincing words let's dive straight into the solution to the question above.

We are given the following parameters which are going to help in solving this particular Question.

The mass of broccoli = 86g of broccoli, mass of carbohydrates present = 6g of carbohydrates, the mass of protein present = 2.6g of protein and the mass of fat present = 0.3g of fat.

Therefore, the nutritional energy content (in Calories) = (6 × 4) + (2.6 × 4) + (0.3 × 9) = 10.4 + 24 + 2.7 = 37.1

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5 0
2 years ago
_Fe2O3 + 2CO —&gt; _Fe + _CO2
soldi70 [24.7K]
<h3>Answer:</h3>

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

<h3>Explanation:</h3>

Concept tested: Balancing of chemical equations

  • A chemical equation is balanced by putting appropriate coefficients on the products and reactants of the equation.
  • Balancing chemical equations ensures that chemical equations obey law of conservation of mass.
  • In this case; to balance the above equation we put the coefficients, 1, 3, 2, and 3 on the reactants and products.
  • Therefore; the balanced chemical equation for the reaction is;

      Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

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