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Ksenya-84 [330]
3 years ago
15

What happens in this reaction and why? hept-3-yne + Br2 -->

Chemistry
1 answer:
maw [93]3 years ago
6 0

Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)

The reaction between hept-3-yne and bromine produces <em>trans</em>-3,4-dibromo-3-heptene.

The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.

In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.

The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.

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<h3>Answer:</h3>

72.19 g HCl

<h3>Explanation:</h3>

We are given the reaction between hydrogen gas and chlorine gas as;

H₂(g) + Cl₂(g) → 2HCl(g)

Mass of hydrogen gas that reacts is 2 g

We are required to determine the amount of HCl produced

<h3>Step 1: Determine the number of moles of H₂ used </h3>

Moles = Mass ÷ molar mass

Molar mass of Hydrogen gas = 2.02 g/mol

Thus;

Moles = 2 g ÷ 2.02 g/mol

          = 0.99 moles

<h3>Step 2: Moles of HCl produced </h3>

From the reaction equation, 1 mole of hydrogen gas reacts to produce 2 moles of HCl

Therefore, the mole ratio of H₂ : HCl = 1 : 2

Thus, moles of HCl = 0.99 moles × 2

                                = 1.98 moles

<h3>Step 3: Mass of HCl produced </h3>

To calculate mass we multiply the number of moles by molar mass

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Thus, the amount of HCl produced during the reaction is 72.19 g

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