The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
mn=mass of neutron=<span>1.67 10^-27 kg
</span><span>m nucleus= 5
Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5= - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19= -5.625 10^35 eV
the final answer is </span><span>Eb /nucleon </span><span>= -5.625 x10^35 eV</span>
Answer:
70 m.
Explanation:
Given,
Frequency, f = 20 HZ
speed of sound, v = 1400 m/s
wavelength of the waves = ?
we know,
v = f λ



Hence, the wavelength of the wave is equal to 70 m.
Answer:
3WGGRGWERGRG
Explanation:
GERAGAETGAERR GHERUERHGRRGF;SBDF;JKSRDMFNSDFLDGGD;GDVF
<h2>
Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>
Explanation:
Kinetic energy = 0.5 x Mass x Velocity²
For ball of mass 2 kg
Mass, m = 2 kg
Velocity, v = 4 m/s
Kinetic energy = 0.5 x 2 x 4² = 16 J
For ball of mass 4 kg
Mass, m = 4 kg
Velocity, v = 2 m/s
Kinetic energy = 0.5 x 4 x 2² = 8 J
Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball