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natima [27]
1 year ago
5

2. What process does water redeposit into a lake in the form of rain?

Physics
1 answer:
weqwewe [10]1 year ago
5 0

The process that water redeposit into a lake in the form of rain is precipitation.

<h3>What is water runoffs?</h3>

Water runoff occurs when there is more water than land can absorb.

The water flows across the surface of the land and into nearby creeks, streams, or lakes.

Runoff can come from both natural processes and human activity.

When rain falls to the earth from clouds and runs downhill into rivers and lakes.

During evaporation, the water turns from liquid into gas, and moves from oceans and lakes into the atmosphere where it forms clouds.

<h3>What is precipitation?</h3>

Precipitation is any liquid (rain) or frozen water that forms in the atmosphere and falls back to the Earth, for example it could fall on land or into lakes and rivers.

Thus,  the process that water redeposit into a lake in the form of rain is precipitation.

Learn more about precipitation here: brainly.com/question/1783904

#SPJ1

You might be interested in
In a rectangular coordinate system a positive point charge q=6.00×10−9 C q=6.00×10−9 C is placed at the point x = +0.150 m, y =
jeka94

Answer:

a) E_net = 0

b) E_net = 2663.7 N/C

c) E_net = 525.915 N/C

d) E_net = 1380.864 N/C

Explanation:

Given:

- The positions of charges are = ( 0.15 , 0 ) & (-0.15 , 0 )

- Both charges have equal magnitude Q = +6*10^-19 C

Find:

Find the magnitude of the electric field at:

(a) the origin;

(b) x = 0.300 m, y = 0;

(c) x = 0.150 m, y = -0.400 m;

(d) x = 0, y = 0.200 m.

Solution:

- The Electric field generated by an charged particle Q at a distance r is given by:

                                 E = k*Q / r^2

- Where, k is the coulomb's constant = 8.99 * 10^9

Part a) @ ( 0 , 0 )

- First we see that the charges +Q_1 and +Q_2 produce an electric field equal but opposite in nature because the distance r from origin and magnitude of charge is same. So the sum of Electric fields:

                                 E_1 + E_3 = 0

Part b) @ ( 0.3 , 0 )

- The Electric field due to charge Q_1 is expressed by:

                                  E_1 = k*Q_1 / r_1^2

Where the distance r from first charge to ( 0.3 , 0 ) is:

                                  r_1 = 0.3 - 0.15 = 0.15 m

- The Electric field due to charge Q_2 is expressed by:

                                  E_2 = k*Q_2 / r_2^2

Where the distance r from second charge to ( 0.3 , 0 ) is:

                                  r_2 = 0.3 - (-0.15) = 0.45 m

- The net Electric Field at point ( 0.3 , 0 ) is:

                                  E_net = E_1 + E_2

                                  E_net = k*Q* ( ( 1 / r_1^2) + ( 1 / r_2^2) )

Plug values in:

                                 E_net = (8.99*10^9)*6*10^-9* ( ( 1 / 0.15^2) + ( 1 / 0.45^2)))

                                 E_net = 2663.7 N/C

Part c) @ ( 0.15 , -0.4 )

- The Electric field due to charge Q_1 is expressed by:

                                  E_1 = k*Q_1 / r_1^2

Where the distance r from first charge to ( 0.15 , -0.4 ) is:

                                  r_1 = 0.4 m

- The Electric field due to charge Q_2 is expressed by:

                                  E_2 = k*Q_2 / r_2^2

Where the distance r from second charge to ( 0.15 , -0.4 ) is:

                                  r_2 = sqrt (0.3^2 + 0.4^2) = 0.5 m

- The net Electric Field at point ( 0.15 , -0.4 ) is:

                                  E_vertical = E_1 + E_2*sin(a)

                                  E_horizontal = E_2*cos(a)

Where,  a is the angle between x -axis and point  ( 0.15 , -0.4 ):

                                  cos(a) = 0.3 / r_2 = 0.3/0.5 = 3/5

                                  sin(a) = 0.4 / r_2 = 0.4/0.5 = 4/5

Hence,

                              E_vertical = k*Q* ( ( 1 / r_1^2) + ( sin(a)/ r_2^2)

                              E_v = (8.99*10^9)*6*10^-9* ( ( 1 / 0.4^2) + ( 0.8 / 0.5^2 )

                              E_v = 509.733 N/C

And,

                              E_Horizontal = k*Q* ( ( 1 / r_1^2) + ( sin(a)/ r_2^2)

                              E_h = (8.99*10^9)*6*10^-9*( 0.6 / 0.5^2 )

                              E_h = 129.456 N/C  

Hence,      

                              E_net = sqrt ( E_vertical^2 + E_horizontal^2)

                              E_net = sqrt ( 509.733^2 + 129.456^2)

                              E_net = 525.915 N/C

                                 

Part d) @ ( 0 , 0.2 )

- The Electric field due to charge Q_1 is expressed by:

                                  E_1 = k*Q_1 / r_1^2

Where the distance r from first charge to ( 0 , 0.2 ) is:

                                  r_1 = sqrt (0.15^2 + 0.2^2) = 0.25 m

- The Electric field due to charge Q_2 is expressed by:

                                  E_2 = k*Q_2 / r_2^2

Where the distance r from second charge to ( 0 , 0.2 ) is:

                                  r_2 = sqrt (0.15^2 + 0.2^2) = 0.25 m

- The net Electric Field at point ( 0 , 0.2 ) is:

                                  E_vertical = E_1*sin(a) + E_2*sin(a)

                                  E_vertical = 2*E*sin(a)

                                  E_horizontal = 0 ... Equal but opposite magnitude

Where,  a is the angle between x -axis and point  ( 0 , 0.2 ):

                                sin(a) = 0.2 / r_2 = 0.2/0.25 = 4/5                                

Hence,

                              E_vertical = 2*k*Q*sin(a)*( 1 / r_1^2)

                              E_v = 2*0.8*(8.99*10^9)*6*10^-9* ( 1 / 0.25^2)

                              E_v = 1380.864 N/C  

Hence,      

                              E_net = E_vertical                              

                              E_net = 1380.864 N/C

5 0
3 years ago
While wearing rubber-soled shoes, you rub a helium balloon on your sweater. The balloon becomes negative charged. Now release th
Sonja [21]

Answer: you are creatively creating static electricity.

Explanation:

6 0
3 years ago
What is generally TRUE about diagnosing psychological disorders?
Allisa [31]

The statement that says "Psychological disorders can be very difficult to diagnose" is true about diagnosing psychological disorders.

<h2>What are psychological disorders?</h2>

Psychological disorders are those mental, behavioral, emotional and thinking conditions that interfere with the normal performance of the individual in society.

  • Mental disorders are psychiatric conditions that are expressed in a syndrome, verifiable from different diagnostic criteria.

  • The steps to obtain a diagnosis include a medical history, physical examination, and possibly laboratory tests and a psychological evaluation.

Therefore, we can conclude that a psychological disorder is an alteration in the mental balance of a person that requires specialized attention adapted to the characteristics of the dysfunction.

Learn more about psychological disorders here: brainly.com/question/6367767

3 0
2 years ago
A 58.72 kg person holding a steel ball stands motionless on a frozen lake.
Sever21 [200]

Answer:16.44 kg

Explanation:

Apex ;)

4 0
3 years ago
Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble
Neporo4naja [7]

Answer:

2.4 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

4 0
3 years ago
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