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3 years ago

It is a good idea to read or exchange text messages during all of the following times EXCEPT:

Physics

2 answers:

Dafna11 [192]3 years ago

8 0

Answer: A while driving a car. It is unsafe

Alexxx [7]3 years ago

6 0

Answer:

It is a good idea to read or exchange text messages during all of the following times except while driving a car.

Explanation:

Eating lunch and using your phone is very safe. The only way I can see it being bad is if you handed your phone to some toddlers and took it back without wiping it off!

If you're waiting for your appointment or waiting to reach your destination, then there is also no harm. As long as you are not driving the bus or you're not the doctor working on patients while texting, then this should be alright.

This leaves us with driving. The commercials tell us. Common knowledge tells us. Hopefully, parents or colleagues or even your own kids (I've had to do this to my dad countless times before) have told you this...

DO NOT TEXT WHILE DRIVING.

So many accidents happen solely for this reason. People, just put down the phone and wait 'til you're at a red light or, even better, when you reach your destination.

So no, it is not a good idea to read OR exchange text messages while driving. Any other time? Well, go ahead! But if you're in that driver seat and your currently in the road with other cars, take into consideration the fact you are not the only person there. Keep everyone safe and drop that phone!

....

My bad, I got long winded. Hope this helped!

Source(s): TV Commercials, myself.

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Your average speed on the first half of a car trip is 69.0 km/h. How fast do you have to drive on the second half of the trip to

vova2212 [387]

Answer:

13 km/h

Explanation:

Average speed = distance/time

Let the total distance and total time taken for the whole trip be d km and t hours respectively

Average speed for the whole trip = 82 km/h

d = 82t

The distance covered in the first half = d1/2

Time taken = t/2

Average speed = 69 km/h

69 = d1/2 ÷ t/2

d1 = 69t

The distance covered in the second half = d2/2

Time taken = t/2

Let the average sly for the see half be A

A = d2/2 ÷ t/2

d2 = At

d = d1 + d2

82t = 69t + At

At = 82t - 69t

At = 13t

A = 13t/t = 13 km/h

3 0

3 years ago

What is the ratio of escape speed from earth to circular orbital speed? ignore air resistance.

klio [65]

About 40 000 km/h
Here you go:

8 0

3 years ago

Read 2 more answers

a ball is projected upward at time t = 0.00 s from a point on a roof 70 m above the ground. The ball rises, then falls and strik

grin007 [14]

Answer: 17.68 s

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the height of the ball when it hits the ground

$y_{o}=70 m$ is the initial height of the ball

$V_{o}=82m/s$ is the initial velocity of the ball

$t$ is the time when the ball strikes the ground

$g=9.8m/s^{2}$ is the acceleration due to gravity

Having this clear, let's find $t$ from (1):

$0=70m+(82m/s)t-\frac{1}{2}(9.8m/s^{2})t^{2}$ (2)

Rewritting (2):

$-\frac{1}{2}(9.8m/s^{2})t^{2}+(82m/s)t+70m=0$ (3)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (4)

Where:

$a=-\frac{1}{2}(9.8m/s^{2}$

$b=82m/s$

$c=70m$

Substituting the known values:

$t=\frac{-82 \pm \sqrt{82^{2}-4(-\frac{1}{2}(9.8)(70)}}{2a}$ (5)

Solving (5) we find the positive result is:

$t=17.68 s$

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3 years ago

a worker uses a board that is 7 m long to pry up a bolder A small rock is used for the fulcrum and is placed 2.5 m from the resi

e-lub [12.9K]

Answer:

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3 years ago

vector ????⃗ has a magnitude of 17.9 and its direction is 80∘ counter‑clockwise from the x- axis. what are the x- and y- compone

Reika [66]

We have vector $(17.9*cos80^{0},17.9*sin80^{0})$

Therefore,

x component = 17.9 * cos80 degree = 3.108

y component = 17.9 * sin80 degrees = 17.628

<h3>What is a vector?</h3>

An object with both magnitude and direction is referred to be a vector. A vector can be visualized geometrically as a directed line segment, with an arrow pointing in the direction and a length equal to the magnitude of the vector. The vector points in a direction from its tail to its head.

If the magnitude and direction of two vectors match, they are the same vector. This shows that if we move a vector to a different location without rotating it, the final vector will be the same as the initial vector. The vectors that denote force and velocity are two examples. The direction of force and velocity are both fixed. The size of the vector would represent the force's strength or the velocity's corresponding speed.

To know more about vectors, visit:

brainly.com/question/12937011

#SPJ4

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2 years ago