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Ray Of Light [21]
3 years ago
6

It is a good idea to read or exchange text messages during all of the following times EXCEPT:

Physics
2 answers:
Dafna11 [192]3 years ago
8 0

Answer: A while driving a car. It is unsafe

Alexxx [7]3 years ago
6 0

Answer:

It is a good idea to read or exchange text messages during all of the following  times except while driving a car.

Explanation:

Eating lunch and using your phone is very safe. The only way I can see it being bad is if you handed your phone to some toddlers and took it back without wiping it off!

If you're waiting for your appointment or waiting to reach your destination, then there is also no harm. As long as you are not driving the bus or you're not the doctor working on patients while texting, then this should be alright.

This leaves us with driving. The commercials tell us. Common knowledge tells us. Hopefully, parents or colleagues or even your own kids (I've had to do this to my dad countless times before) have told you this...

DO NOT TEXT WHILE DRIVING.

So many accidents happen solely for this reason. People, just put down the phone and wait 'til you're at a red light or, even better, when you reach your destination.

So no, it is not a good idea to read OR exchange text messages while driving. Any other time? Well, go ahead! But if you're in that driver seat and your currently in the road with other cars, take into consideration the fact you are not the only person there. Keep everyone safe and drop that phone!

....

My bad, I got long winded. Hope this helped!

Source(s): TV Commercials, myself.

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Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

E=hf

where

h is the Planck constant

f is the frequency

For the photons in this problem,

f=6.8\cdot 10^9 Hz

So the energy of one photon is

E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J

The number of photons contained in 1.0 mol is

N_A = 6.022\cdot 10^{23} mol^{-1} (Avogadro number)

So the total energy of N_A photons contained in 1.0 mol is

E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J

3 0
3 years ago
Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B​
andreyandreev [35.5K]

Explanation:

Let \textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}} and \textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}

The sum of the two vectors is

\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}

= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}

The difference between the two vectors can be written as

\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}

= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}

8 0
3 years ago
2. A ladder 16cm long weighs 420N and it's centre of gravity is 7m from one end.It is carried horizontally by two boys,each hold
ipn [44]

Answer:

well the answers are 180 and 240 obviously

Explanation:

Download pdf
8 0
2 years ago
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The pulley system below uses a gasoline engine to raise a drill head up through a smooth drill pipe. The engine provides a const
polet [3.4K]

NB: The diagram of the pulley system is not shown but the information provided is sufficient to answer the question

Answer:

Power = 2702.56 W

Explanation:

Let the power consumed be P

Energy expended = E = mgh

height, h = 5 m

E = 80 * 9.8 * 5

E = 3920 J

Power = \frac{Energy}{time}

To calculate the time, t

From F = ma

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a = 900/80

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From the equation of motion, s = ut + 0.5at^{2}

The drill head starts from rest, u = 0 m/s

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Power, P = E/t

P = 3920/0.0.943

P = 4157.79 W

But Efficiency, E = 0.65

P = 0.65 * 4157.79

Power = 2702.56 W

6 0
3 years ago
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When two tectonic plates collide and form a converging plate boundry, normally one of the plates will slide underneath the other and that is when Subduction occurs.
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