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gregori [183]
4 years ago
10

A flashlight is held at the edge of a swimming pool at a height h = 1.6 m such that its beam makes an angle of θ = 38 degrees wi

th respect to the water's surface. The pool is d = 1.75 m deep and the index of refraction for air and water are n1 = 1 and n2 = 1.33, respectively.
Required:
What is the horizontal distance from the edge of the pool to the bottom of the pool where the light strikes? Write your answer in meters.
Physics
1 answer:
slava [35]4 years ago
6 0

one of the answers that i found was   5.83 m i did some more research and it showed the same answer again. good luck with it. hope i was able to help you.

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A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 22.0 cm. You will investigate th
katen-ka-za [31]

To solve the problem, it is necessary to use the concepts of gravitational force, centripetal force and trigonometric components that can be extrapolated from the statement.

By definition we know that the Force of Gravity is given by

F_g=mg

Where,

m= Mass

g = Gravitational Acceleration

The centripetal force is given by,

F_c = \frac{mv^2}{R}

Where,

m = Mass

v = Velocity

R = Radius

For the case described in the problem, the Force of gravity the net component would be given by sin?, While for the centripetal force the net component is in the horizontal direction, therefore it corresponds to the cos\theta

Then,

F_g = mg sin\theta

F_c = \frac{mv^2}{r}cos\theta

From the radius we have its length but not the net height, which would be given by

r = L sin\theta

So equating the equations we have to

F_g = F_c

mg sin\theta=\frac{mv^2}{r}cos\theta

mg sin\theta=\frac{mv^2}{Lsin\theta}cos\theta

Re-arrange to find v,

v = \sqrt{\frac{gLsin^2\theta}{cos\theta}}

Replacing with our values

v = \sqrt{\frac{(9.8)(22*10^{-2})(sin^2 24)}{cos24}}

v = 0.624

Therefore the tangential velocity of the mass is 0.624m/s

5 0
4 years ago
A 20-N force applied to the handle of a door produces a 44-N output force. What is the AMA of the handle?
Zepler [3.9K]
Method:

44 N / 20 N
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3 years ago
A man pushes a shopping cart at a constant speed. What happens if the man increases the force on the cart?
Bezzdna [24]

Answer:

The cart would speed up.

Explanation:

According to Newton's 1st law, object subjected to no force, or net force 0, would have a constant speed. In our case the cart is initially at constant speed, meaning the man exerts a force that is equal to friction force. If he increases the force on the cart, the net force would no longer be 0. The cart would gain an acceleration and increases its speed.

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IgorC [24]

Answer:

Hey

Your answer would be Earth's atmospheric system

Over time of cousre it will effect Earth's intire surface.

DON'T DRIVE MORE THAT YOU HAVE TO, SAVE THE EARTH!

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Mike and Juan were studying forces and decided to do an experiment. they placed four
lora16 [44]

Answer:

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