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leva [86]
3 years ago
10

What's impulse of force ​

Physics
1 answer:
vekshin13 years ago
6 0

Answer:

The impulse experienced by the object equals the change in momentum of the object. In equation form, F.t = m. Δv. In a collision, objects experience an impulse; the impulse causes and is equal to the change in momentum.

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A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the
Vesna [10]

So, based on the angle values that have been found, the angle of elevation of the nozzle can be <u>16° or 74°</u>.

<h3>Introduction</h3>

Hi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :

\boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}}

With the following condition :

  • \sf{x_{max}} = the farthest distance of the parabolic movement (m)
  • \sf{v_0} = initial speed (m/s)
  • \sf{\theta} = elevation angle (°)
  • g = acceleration due to gravity (m/s²)

<h3>Problem Solving :</h3>

We know that :

  • \sf{x_{max}} = the farthest distance of the parabolic movement = 2.5 m
  • \sf{v_0} = initial speed = 6.8 m/s
  • g = acceleration due to gravity = 9.8 m/s²
<h3>What was asked :</h3>
  • \sf{\theta} = elevation angle = ... °

Step by Step :

  • Find the equation value \sf{\bold{theta}} (elevation angle)

\sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}

\sf{x_{max}  \cdot g = (v_0)^2 \cdot \sin(2 \theta)}

\sf{\frac{x_{max}  \cdot g}{(v_0)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =  \sin(2 \theta)}

\sf{\frac{24.5}{46.24} = \sin(2 \theta)}

\sf{\sin(2 \theta) \approx 0.53}

\sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)}

  • Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.

First Probability

\sf{2 \theta = 32^o + k \cdot 360^o}

\sf{\theta = 16^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 16^o + 0 = 16^o} (T)

→ \sf{k = 1 \rightarrow 16^o + 180^o = 196^o} (F)

Second Probability

\sf{2 \theta = (180^o - 32^o) + k \cdot 360^o}

\sf{2 \theta = 148^o + k \cdot 360^o}

\sf{\theta = 74^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 74^o + 0 = 74^o} (T)

→ \sf{k = 1 \rightarrow 74^o + 180^o = 254^o} (F)

\boxed{\sf{\therefore \theta \{16^o , 74^o\} }}

<h3>Conclusion</h3>

So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.

8 0
3 years ago
A metal object is suspended from a spring scale. The scale reads 920 N when the object is suspended in air, and 750N when the ob
Ostrovityanka [42]

17.3 L.

<h3>Explanation</h3>

The object appears 920 - 750 = 170\;\text{N} lighter in water than in the air. Water has supplied that 170 N of buoyant force.

The size of the buoyant force on an object in water is the same as the weight of water that the object has displaced. The buoyant force on the metal object here is 170 N. The object must have displaced water of the same weight.

g = 9.81 \;\text{N}\cdot\text{kg}^{-1}.

Mass of water displaced:

\text{Mass} = \dfrac{\text{Weight}}{g} = \dfrac{170}{9.81} = 17.3 \;\text{kg}.

Volume of water displaced:

The density of water at room temperature is 1.000\;\text{kg}\cdot\text{dm}^{-3}. Each kilogram of water will occupy a volume of 1 dm³ (one cubic decimeter), which is the same as 1 L (one liter).

V = \dfrac{\text{Mass}}{\text{Density}} =\dfrac{m}{\rho} = \dfrac{17.3\;\text{N}}{1.000\;\text{kg}\cdot\text{dm}^{-3}} = 17.3\;\text{dm}^{-3}=17.3\;\text{L}.

Volume of the object:

The object is completely under water. As a result, the volume of the object will be the same as the volume of water displaced. The volume of the object is also 17.3 L.

3 0
3 years ago
On average how fast does the radiation spread from an atom-bomb?
devlian [24]

Answer:

around 30 grays

Explanation:

Hope this helps :)

7 0
3 years ago
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Light travels slowest in high density media, faster in lower density media, and fastest in low density media.
Anit [1.1K]

Based on what we know, we can confirm that the wave behavior being observed when light passes through media of different densities is refraction.

<h3>What is refraction?</h3>

This is a term used to explain the behavior of light as it moves through distinct mediums. This behavior includes a change in direction of the light due to its change in speed.

Therefore, the wave behavior being observed when light passes through media of different densities is refraction.

To learn more about light waves visit:

brainly.com/question/3004869?referrer=searchResults

7 0
2 years ago
Which lab equipment is used as a cover to prevent heated materials from splattering out of the container and as a holding plate
faltersainse [42]

Watchglass is a lab equipment that is used as a cover to prevent heated materials from splattering out of the container and as a holding plate for hot or flammable materials

<u>Explanation:</u>

Watch glass is an equipment used as a cover to prevent heated materials from splattering out of the container and as a holding plate for hot or flammable materials. It is a kind of concave glass which is also used to evaporate a liquid and also provides good air circulation which is used during cooking. The name watchglass was derived as they are see through and so similar to pocket glasses.

3 0
3 years ago
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