1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
il63 [147K]
3 years ago
8

A student sects a leaf of length 7.2 cm to draw. Her drawing is 28.8 cm in length. What is the magnification of the drawing?

Physics
1 answer:
Alina [70]3 years ago
7 0

Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

28.8 cm/7.2 cm = 4

You might be interested in
What type of simple machine can pinball machine flippers can be explained?
vaieri [72.5K]

Answer:

Your pinball machine was built using two kinds of simple machines: a lever and an inclined plane. The lever shot the marble to the top of the box with lots of force. The inclined planes made the marble wind its way down to the bottom.

6 0
2 years ago
What type of noise is most difficult to remove from a digital signal? why?
Lilit [14]
Interference if the hardest to remove due to the superposition of the frequencies of the radio waves
8 0
3 years ago
Letter A on this diagram is an example of
MrRa [10]
The answer is A vaporization 

5 0
4 years ago
Read 2 more answers
A softball is thrown from the origin of an X-Y coordinate system with an initial speed of 18 m/s at an angle of 35 degrees above
Goshia [24]
Vo = 18 m/s
angle 35 degrees

1) Components of the initial velocity
 
Vox = Vo*cos(35) = 18*cos(35) m/s = 14.74 m/s
Voy = Vo* sin(35) = 18*sin(35) m/s = 10.32 m/s

2) Equations of postion:

x = Vox*t
y = Voy*t - gt^2 / 2

3) Calculations

A) t = 0.5 s, t = 1.0 st = 1.5 s, t = 2.0 s

x = 14.74 * t

t = 0.5 s => x = 14.74 m/s * 0.5s = 7.37 m

t = 1.0 s => x = 14.74 m/s * 1.0s = 14.74 m

t = 1.5s => x = 22.11 m

t = 2s => x = 29.48 m

B)

y = Voy*t - gt^2 / 2

Voy = 10.32 m/s
g = 10 m/s (approximation)

y = 10.32*t - 5t^2

t = 0.5 s=> y = 3.91m

t = 1 s => y = 5.32m

t = 1.5 s => y = 4.23m

t = 2 s => y = 0.64 m



7 0
3 years ago
If an athlete leaps vertically at 4.0m/s, what maximum height does he reach?
joja [24]
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration: g=-9.81~m/s^2, and where the negative sign means it points downwards, against the direction of the motion.

Therefore, we can use the following formula to solve the problem:
v_f^2 = v_i^2 + 2gS
where v_i=4~m/s is the initial vertical velocity of the athlete, v_f=0 is the vertical velocity of the athlete at the maximum height (and v_f=0~m/s at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
S= \frac{v_f^2-v_i^2}{2g}=0.82~m

3 0
3 years ago
Other questions:
  • if a bowling ball and a golf ball or move at the same velocity, which one would have more momentum? Why?
    8·2 answers
  • A horse ran at a constant speed for 4 hours. Then, it decreased its speed by 7 mph for the
    5·1 answer
  • An object is placed between two plain mirrors which make angle 45 degree with each other. Distance between all adjacent images a
    13·1 answer
  • Which of these would have particles with the highest kinetic energy? Ice Water Water Vapor
    5·2 answers
  • Identical rays of light in air are refracted upon entering three transparent materials:
    8·1 answer
  • A simple pendulum with a length of 2 m oscillates on the Earth's surface. What is the period of oscillations?
    13·1 answer
  • What is the motion of an apple when it falls from a tree ? a)Constant b)accelerating c)decelerating d)zero​
    11·1 answer
  • 4. Why do you think people in south Louisiana specialize in seafood?
    13·1 answer
  • A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app
    5·1 answer
  • I did all the work but I would appreciate it if someone checks my graph and make sure I graphed it right. thank you !​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!