I think D. It starts at (0.0) and goes to the correct points so it makes sense
Neutrons have a zero charge but consist of mass.
The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
<h3>How to find the distance between slit and the screen?</h3>
- It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
- We have the expression for slit width w as,
![w=\frac{2*wavelength*d}{a}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B2%2Awavelength%2Ad%7D%7Ba%7D)
where, d is the distance between slit and the screen, and a is the slit width.
- Thus, distance between slit and the screen is,
![d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bw%2Aa%7D%7B2%2Awavelength%7D%20%3D%5Cfrac%7B8%2A10%5E%7B-3%7D%2A0.17%2A10%5E%7B-3%7D%7D%7B560%2A10%5E%7B-9%7D%2A2%7D%20%5C%5C%5C%5Cd%3D1.214m)
Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
brainly.com/question/13088191
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Answer:
t = 2.5 hours
Explanation:
given,
speed of the bike for t time= 18 mi/h
final speed of the bike after t time = 12 mi/h
total distance, D = 69 miles
total time, T= 4.5 hour
time for which speed of the bike is 18 mi/h = ?
we know distance = speed x time
now,
18 x t + 12 (4.5 - t) = 69
6 t + 54 = 69
6 t = 15
t = 2.5 hours
The bike was at the speed of 18 mi/h for 2.5 hours.