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Oliga [24]
3 years ago
13

An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the

time it takes the object to complete one horizontal circle?
P.S. : I know the answer is 1.18 seconds but I just don’t know how to get there. Can someone explain to me how to do it? Thanks
Physics
1 answer:
Igoryamba3 years ago
7 0

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.  

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration (a), measured in meters per square second, is entirely centripetal and is expressed as:

a = \frac{4\pi^{2}\cdot R}{T^{2}} (1)

Where:

T - Period of rotation, measured in seconds.

R - Radius of rotation, measured in meters.

If we know that a = 26.36\,\frac{m}{s^{2}} and R = 0.93\,m, then the time taken by the object to complete one revolution is:

T^{2} = \frac{4\pi^{2}\cdot R}{a}

T = 2\pi\cdot \sqrt{\frac{R}{a} }

T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }

T \approx 1.180\,s

The object takes approximately 1.180 seconds to complete one horizontal circle.  

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