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Masja [62]
3 years ago
5

How do scientists determine the number of neutrons in an isotope of an atom?

Physics
1 answer:
xz_007 [3.2K]3 years ago
5 0
D subtract the atomic number from the atomic mass

N = A - Z
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What does this circle graph tell you about water on Earth? (2 points)
vekshin1

Answer:

ocean covers 71 percent of the earth

8 0
3 years ago
Suppose that the sun shrank in size but that its mass remained the same. What would happen to the orbit of the earth?
Minchanka [31]

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

G\frac{Mm}{r^2} = m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

r=\frac{GM}{v^2}

Also,

v=\omega r

where \omega is the angular velocity of the Earth's orbit. So we can rewrite the equation as

r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

6 0
3 years ago
In order to make an object stop, what direction does the unbalanced force need to be applied?
nataly862011 [7]
Against the object in motion
6 0
4 years ago
What is the mass of a 1.2N book?
const2013 [10]

2.8 kg .............is the mass of a 1.2 N book.

7 0
3 years ago
Read 2 more answers
A motorcycle that is slowing down uniformly covers 2.0 successive km in 80 s and 120 s, respectively. Calculate (a) the accelera
8090 [49]

Answer:

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

Explanation:

given data

distance d1 = 1 km

distance d2 = 2 km

time  t1 = 80 s

time t2 = 120 s + 80s = 200 s

to find out

acceleration and velocity at beginning and end

solution

we apply here law of motion that is

d = vt + 1/2×at²    

put value

1000 = v(80) + 1/2×a(80)²           ........................1

and

2000 = v(200) + 1/2×a(200)²      ........................2

so from equation 1 and 2 we get a and v

a = -0.042 m/s² and

v = 14.167 m/s

so by kinematic final velocity will be

V² = v² + 2ad

V² = (14.167)² + 2×(-0.042)×(2000)

V²  = 32.70

V = 5.7183 m/s

so

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

8 0
3 years ago
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