Y=mx+b m=-3/4 (1,3)
3=-3/4(1)+b
3=-3/4+b
b=3 3/4
y=-3/4+3 3 3/4
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse.
(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.)

Where

is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is:

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis.
The major axis in this case is that of the y-axis. In other words,
So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are:

&

I really hope this helped you! (Partially because I spent a lot of time on this lol)
Sincerely,
~Cam943, Junior Moderator
If AM=10, then AC=10 because both are radii. TC is a diameter so that’ll just be the radius doubled. TC=20!
Answer:
See explanation for matching pairs
Step-by-step explanation:
Equations
(1)
(2)
(3)

Solutions



Required
Match equations with solutions
(1)
and
Make x the subject in: 

Substitute
in



Collect like terms


Solve for y

Recall that: 


So:

(2)
and
Make y the subject in

Substitute
in 


Collect like terms


Solve for x

Solve for y in 



So:

(3)
and 
Make y the subject in 

Substitute
in

Collect like terms


Solve for x

Solve for y in 


So:
