Answer:
161.54 g of N₂
Explanation:
The balanced equation for the reaction is given below:
2NaN₃ —> 2Na + 3N₂
Next, we shall determine the mass of NaN₃ that decomposed and the mass of N₂ produced from the balanced equation. This is illustrated below:
Molar mass of NaN₃ = 23 + (3×14)
= 23 + 42 = 65 g/mol
Mass of NaN₃ from the balanced equation = 2 × 65 = 130 g
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mass of N₂ from the balanced equation = 3 × 28 = 84 g
SUMMARY:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Finally, we shall determine the mass of N₂ produced by the decomposition of 250 g of NaN₃. This can be obtained as follow:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Therefore, 250 g of NaN₃ will decompose to produce
= (250 × 84)/130 = 161.54 g of N₂
Thus, 161.54 g of N₂ were obtained from the reaction.
