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enot [183]
4 years ago
15

How is the game pressure of a gas related to its concentration of particles

Chemistry
2 answers:
Nata [24]4 years ago
7 0
Found this on the web! "The particles of gases are negligibly small compared to the distance between them, ... This is because an increase in the number of particles in the same volume will increase the number of collisions to the walls of the container, which causes pressure to increase."



hope this helps

much love. :)
madreJ [45]4 years ago
7 0

Explanation:

According to ideal gas equation, PV = nRT.

When more is the concentration of particles of a gas it means more number of molecules or more number of moles are present.

As pressure is directly proportional to number of moles of a gas. Therefore, when there are more number of moles of a gas then there will be more number of collisions.

As a result, there will be increase in pressure.

Thus, we can conclude that the game pressure of a gas is directly related to its concentration of particles.

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Draw a Lewis structure for C2H3Cl . Include all hydrogen atoms and show all unshared electron pairs. None of the atoms bears a f
Korvikt [17]

Answer:

See attached picture.

Explanation:

Hello!

In this case, since C2H3Cl is an organic compound we need a central C-C parent chain to which the three hydrogen atoms and one chlorine atom provides the electrons to get all the octets except for H as given on the statement.

In such a way, on the attached picture you can find the required Lewis dot structure without formal charges and with all the unshared electron pairs, considering there is a double bond binding the central carbon atoms in order to compete their octets.

Best regards!

5 0
3 years ago
How many moles of glucose can be produced
Arturiano [62]

Answer:

moles of glucose

<u>2.3166 moles of glucose</u>

<u></u>

Explanation:

The balance reaction for the formation of glucose is :

6CO_{2}+6H_{2}O\rightarrow C_{6}H_{12}O_{6}+6O_{2}

here , CO2 = carbon dioxide

H2O = water

C6H12O6 = glucose

O2 = Oxygen

According to this equation :

6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2

We are asked to calculate the mole of Glucose from carbon dioxide.

So,

6 mole of CO2  produce = 1 mole of C6H12O6

1 mole of CO2 will produce =

\frac{1}{6} moles of glucose

13.9 moles of CO2 will produce :

\frac{1}{6}\times 13.9

=2.3166 moles of glucose

Note : first , Always calculate for one mole (By dividing)

. After this , multiply the answer with the moles given.

Always write the substance whose amount is asked(glucose) to the right hand side

5 0
4 years ago
4570 distance in kilometers
faust18 [17]
4570 distance in kilometers is 0.116078 hope this helps :)
4 0
3 years ago
Are ions of alkali metals larger or smaller than ions of alkaline earth metals from the same period
PtichkaEL [24]
Because size of an atom INCREASES from top to bottom and DECREASES from left to right on the periodic table. If to elements are in the same period they can't increase in size based on the up or down trend. Instead, notice that Alkali Metals are LEFT of Alkaline Earth Metals. Therefore, the Alkali Metal will be larger than the Alkaline Earth Metals.
7 0
4 years ago
What is the empirical formula for a compound that contains 79.86 % iodine and 20.14 % oxygen by mass?
serg [7]

Answer:

IO₂

Explanation:

We have been given the mass percentages of the elements that makes up the compound:

Mass percentage given are:

Iodine = 79.86%

Oxygen = 20.14%

To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:

> Express the mass percentages as the mass of the elements of the compound.

> Find the number of moles by dividing through by the atomic masses

> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.

> The ratio is the empirical formula of the compound.

Solution:

I O

% of elements 79.86 20.14

Mass (in g) 79.86 20.14

Moles(divide by

Atomic mass) 79.86/127 20.14/16

Moles 0.634 1.259

Dividing by

Smallest 0.634/0.634 1.259/0.634

1 2

The empirical formula is IO₂

7 0
3 years ago
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