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Dmitry_Shevchenko [17]
3 years ago
14

A system increases in internal energy by 80 J and 50 J of work are done on it at the same time. What is the heat change of the s

ystem
Physics
1 answer:
marusya05 [52]3 years ago
4 0

Answer:

The heat change of the system is 30 J.

Explanation:

Given;

increase in internal energy of a system, ΔU = 80 J

work done on the system, W = 50 J

The heat change of the system can be calculated from first law of Thermodynamics;

ΔU = Q - W

where;

Q is the heat absorbed by the system

W is the work done by the system (negative when work is done by the system and positive when work is done on the system)

Since work was done on the system the increase internal energy is given as;

ΔU = Q  + W

ΔU  - W = Q

80 J - 50 J = Q

30 J = Q

Therefore, the heat change of the system is 30 J.

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Answer:

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Which of these systems is an oscillator? A. A barrel rolling down the hill B. A child sitting on a swing a skater falling on the
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Answer:

Option B:

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Explanation:

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An oscillator is a system that moves in such a way that it reverses its direction after a period of time. It can be seen as a "to-and-fro" motion.

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2 years ago
Solar evaporation ponds are shallow so that the sun can heat them up, causing the water to evaporate, which increases the salt c
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B. stearothermophilus and S. ruber

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B. stearothermophilus and S. ruber

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3 years ago
A circular coil of wire of radius 5.0 cm has 20 turns and carries a current of 2.0 A. The coil lies in a magnetic field of magni
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U = n*I*A

But Area A is given as pi*radius² since it is a circular coil

Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is

A = 3.142*(0.05)² =7.86*EXP {-3} m²

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Torque = B x U =B*U*Sine(theta)

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