Answer:
Vi = 24.14 m/s
Explanation:
If we apply Law of Conservation of Energy or Work-Energy Principle here, we get: (neglecting friction)
Loss in K.E of the Rock = Gain in P.E of the Rock
(1/2)(m)(Vi² - Vf²) = mgh
Vi² - Vf² = 2gh
Vi² = Vf² + 2gh
Vi = √(Vf² + 2gh)
where,
Vi = Rock's Speed as it left the ground = ?
Vf = Final Speed = 17 m/s
g = 9.8 m/s²
h = height of rock = 15 m
Therefore,
Vi = √[(17 m/s)² + 2(9.8 m/s²)(15 m)]
Vi = √583 m²/s²
<u>Vi = 24.14 m/s</u>
The part of the atom that accounts for electricity is the electron. The correct option among all the options given in the question is option "D". Electrons are capable of moving from one atom to another very easily. The flow of the electrons is actually responsible for electricity to pass. When one electron starts moving in one direction, the other starts following it and this results in the flow of electricity.
Answer:
1. external force;not change
2. all of the above
Bonus!!!!!!
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The frequency heard by an observer in the moving car as he approaches the police car is 558.6 Hz.
<h3>Frequency hear by the observer</h3>
The frequency heard by the observer is calculated by applying the principle of Doppler effect.
f₀ = f'[(v/v - vs)]
where;
- f₀ is the observed frequency
- v is speed of sound = 343 m/s
- vs is the speed of the source
f₀ = 500[(343 / 343 - 36)]
f₀ = 500(343/307)
f₀ = 558.6 Hz
Thus, the frequency heard by an observer in the moving car as he approaches the police car is 558.6 Hz.
Learn more about frequency here: brainly.com/question/10728818
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