Answer:l ectrons will occupy a p orbital only after the s orbital is full
Explanation: Electrons can begin to occupy energy levels with the next highest integer designation only after all of the orbitals on the energy level below it are occupied.
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Answer:
13.92 %
Explanation:
Mass of
= 12.5221 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.0536 moles
According to the given reaction,

1 mole of
is formed from 1 mole of 
Thus,
0.0536 moles of
is formed from 0.0536 moles of 
Moles of
= 0.0536 moles
Moles of sulfur in 1 mole
= 1 mole
Moles of sulfur in 0.0536 mole
= 0.0536 mole
Molar mass of sulfur = 32.065 g/mol
Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g
Mass of ore = 12.3430 g
Mass % =
=
= 13.92 %
I don’t know what is your problem
Step one write the chemical equation for reaction
= Ag2O + 2(C10H10N4SO2)---> 2 ( AgC10H9N4SO2)
The reacting ratio of Ag2O to AgC10H9N4SO2 is 1:2 from the reaction above
step 2; find the number of moles of AgC10H9N4SO2
that is mass/molar mass
The molar mass of AgC10H9N4SO2 = 107.86 +(12 x10) + (1 x 9) + (4 x 14) +32 +(16 x2) =356.86g/mol
moles is therefore= 25g/356.86g/mol= 0.07moles
by use of mole ratio the moles of Ag2O= 0.0702=0.035moles
mass = moles x molar mass
the molar mass of Ag2O=231.72 g/mol
mass is therefore= 231.72g/mol x 0.035moles= 8.11grams
Answer is: less acetic acid to neutralize it.
Balanced chemical reaction of sodium bicarbonate solution and acetic acid: NaHCO₃(aq) + CH₃COOH(aq) → CH₃COONa(aq) + H₂O(l) + CO₂(g).
According to chemical reaction: n(NaHCO₃) : n(CH₃COOH) = 1 : 1.
Stronger solution of sodium bicarbonate (NaHCO₃), more acetic acid (CH₃COOH) is neeed for neutralization.