Compound B contains 92.31% carbon and 7.69% hydrogen. Determine the empirical formula of B

Chemistry

2 answers:

qwelly [4]3 years ago

6 0

Answer: CH

Explanation: To calculate the empirical formula of the compound we must first find the number of moles by using the mass of each element.

C= 92.31 g x 1mole C / 12 g C

= 7. 69 moles C

H = 7.69 g H x 1 mole H/ 1 g H

= 7.69 moles H

Next is divide each answer on the lowest number of moles

C = 7.69 / 7.69 = 1

H = 7.69 / 7.69 = 1

So the ratio is 1:1 or CH

tester [92]3 years ago

5 0

Answer:C H

Explanation:

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What mass of nitrogen is needed to fill an 855 L tank at STP?

scoundrel [369]

Answer:

It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C or 273.15 °K are used and are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, in this case:

P= 1 atm
V= 855 L
n= ?
R= 0.082 $\frac{atm*L}{mol*K}$
T= 273.15 K

Replacing:

1 atm* 855 L= n* 0.082 $\frac{atm*L}{mol*K}$ * 273.15 K

Solving:

$n=\frac{1 atm* 855 L}{0.082\frac{atm*L}{mol*K} *273.15 K }$

n= 38.17 moles

Being the molar mass of nitrogen N2 equal to 28 g / mol, you can apply the following rule of three: if there are 28 grams in 1 mole, how much mass is there in 38.17 moles?

$mass=\frac{38.17 moles*28 grams}{1 mole}$