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3241004551 [841]
3 years ago
7

I dont know how to do percent error.

Chemistry
1 answer:
guapka [62]3 years ago
8 0

Answer:

I'm pretty sure its the percent difference between the two (starting mass and mass retrieved)

Explanation:

Don't blame me if I'm wrong :x

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_______ particles move very fast and freely.<br><br> A.Gas<br><br> B.Solid<br><br> C.Liquid
inn [45]
The answer is A. Gas particles!
6 0
3 years ago
From where in the solar system did scientists conduct their spectral anaylses in 1948? How do you know?
Kryger [21]

Answer:

They conducted it from earth

Explanation:

There had never been anything capable of observing it from space launched at that time because Sputnik wasn't even launched

3 0
3 years ago
An air sample contains 0.044% CO2? If the total pressure is 750 mm Hg. What is the partial pressure of CO2?2?
Aleksandr [31]
Partial pressure=mole fraction×Pt
x=0.044÷44(maolarmass of CO2)×Pt
x=0.044÷(44)2×Pt
x=5×10^-4×Pt
x=5×10^-4×Pt
where Pt:1atm=760mmHg
xatm=750mmHg
750×1÷760=0.99
now;5×10^-4×099=4.95×10^-4.
Pt=4.95×10^-4
8 0
3 years ago
An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
Help..................................................................:)
34kurt

Answer:

ppppp

Explanation:

4 0
3 years ago
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