(Missing in your question ):
we have the following reaction:
A(aq) ↔ 2 B(aq)
and Kc = 7.02 x 10^-6 at 500K
So at equilibrium,
Kc = [Products] / [ reactants]
= [B]^2 / [A]
we have [A] = 3.3 m and Kc is given= 7.02 x10^-6
by substitution:
7.02x10^-6 = [B]^2 / 3.3
∴[B]^2 = 2.3 x 10^-5
∴[B] = 0.005 m
Answer:
the answer is 1.17
Explanation:
D= m/v
=2.63/2.25=1.17g/mL
I don't know if it will sink or not
Hope this will help you ❤️
Answer:
brown precipitate.. d.. option
Answer:
The process by which a body of water becomes enriched in dissolved nutrients (such as phosphates) that stimulate the growth of aquatic plant life usually resulting in the depletion of dissolved oxygen.