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2 years ago

Octasilicon nonanitride --- Covalent compound What is the chemical formula?

Chemistry

1 answer:

Naddika [18.5K]2 years ago

4 0

Answer:

Naming binary (two-element) covalent compounds is similar to naming simple ionic compounds. The first element in the formula is simply listed using the name of the element. The second element is named by taking the stem of the element name and adding the suffix -ide.

Explanation:

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A closed container contains 0.40 moles of argon gas at 25 °C and a pressure of 740 torr. The container is heated to 125 °C and t

Ksivusya [100]

The number of moles of argon that must be released in order to drop.

Solution:

Initial Temperature = 25°c = 298 K

Final Temperature =125 °c = 398 K

Initial Moles (n1) = 0.40 mole

Now, Using the ideal gas law,

n1T1 = n2T2

0.400×298 = n2 × 398

n2 = 0.299 mol

Moles of Argon released

= 0.400-0.299

= 0.100 mol.

Pressure and force are related. That is using the physical equations if you know the other, you can calculate one using pressure = force/area. This pressure can be reported in pounds per square inch, psi, or Newtons per square meter N/m2. Kinetic energy causes air molecules to move faster. They hit the walls of the container more often and with greater force. The increased pressure inside the can may exceed the strength of the can and cause an explosion.

Learn more about The temperature here:-brainly.com/question/24746268

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7 0

1 year ago

2) 2KClO3 --> 2KCl + 3O2

aleksandrvk [35]

$2 \text{ KClO}_3 \to 2 \text{ KCl}+3\text{ O}_2$

$2 \text{ mols of KClO}_3 \equiv 3 \text{ mols of O}_2$

$19 \text{ mols of KClO}_3 \equiv 3\cdot 9,5 \text{ mols of O}_2$

$\boxed{19 \text{ mols of KClO}_3 \equiv 28,5 \text{ mols of O}_2}$

$2 \text{ mols of KClO}_3 \equiv 2 \text{ mols of KCl}$

$62 \text{ mol of KClO}_3 \equiv 62 \text{ mol of KCl}$

Using the atomic mass given in the periodic table:

$62\cdot(39+35,5+16\cdot3) \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$62\cdot122,5 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$7595 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$\boxed{7,595 \text{ kg of KClO}_3 \equiv 62 \text{ mol of KCl}}$

$2 \text{ KCl}+3\text{ O}_2\to 2 \text{ KClO}_3$

$3 \text{ mols of O}_2 \equiv 2 \text{ mols of KCl}$

Using the atomic mass given in the periodic table:

$3\cdot(2\cdot 16) \text{ g of O}_2 \equiv 2\cdot(39+35,5) \text{ g of KCl}$

$96\text{ g of O}_2 \equiv 149\text{ g of KCl}$

$\dfrac{39}{149}\cdot 96\text{ g of O}_2 \equiv \dfrac{39}{149}\cdot 149\text{ g of KCl}$

$\boxed{25,13\text{ g of O}_2 \equiv 39\text{ g of KCl}}$

This result is an aproximation.

8 0

2 years ago

A spring scale is best defined as

Black_prince [1.1K]

A spring scale is a type of weighing scale, it works because it uses a spring that is proportional to the distance that the spring is from its resting position.

3 0

2 years ago

Consider the following reaction at equilibrium. 2CO2 (g) 2CO (g) + O2 (g) H° = -514 kJ Le Châtelier's principle predicts that th

tiny-mole [99]

Answer:

C. at low temperature and low pressure.

Explanation:

Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

For the reaction:

2CO₂(g) ⇄ 2CO(g) + O₂(g), ΔH = -514 kJ.

Effect of pressure:

When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.

The reactants side (left) has 2.0 moles of gases and the products side (right) has 3.0 moles of gases.

So, decreasing the pressure will shift the reaction to the side with higher no. of moles of gas (right side, products), so the equilibrium partial pressure of CO (g) can be maximized at low pressure.

Effect of temperature:

The reaction is exothermic because the sign of ΔH is (negative).

So, we can write the reaction as:

2CO₂(g) ⇄ 2CO(g) + O₂(g) + heat.

Decreasing the temperature will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the temperature, so the equilibrium partial pressure of CO (g) can be maximized at low temperature.

So, the right choice is:

C. at low temperature and low pressure.

7 0

3 years ago

Which two phrases describe the movement of thermal energy due to

Varvara68 [4.7K]

Answer:

D. From the equator to cooler parts of Earth

Explanation:

Thermal energy is always transferred from an area with a higher temperature to an area with a lower temperature. Moving particles transfer thermal energy through a fluid by forming convection currents.

3 0

2 years ago