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3 years ago

Choose the definition for the function. (Picture)

Mathematics

2 answers:

mestny [16]3 years ago

3 0

Answer : A

hope this helps

Evgesh-ka [11]3 years ago

3 0

Answer: B

Step-by-step explanation:

I got it right before

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Solve S=2πrh+πr2 for h

kirill115 [55]

$S= \pi rh+ \pi r^2\ \ \ \ | subtract\ \pi r^2\\\\
s-\pi r^2= \pi rh\ \ \ \ | divide\ by\ \pi r \\\\
\frac{s-\pi r^2}{ \pi r}=h$

3 0

3 years ago

14.

hoa [83]

D
You subtract 5 1/4 (5.25) - 3 3/4 (3.75) = 1 1/2 (1.5)

3 0

3 years ago

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Guys pls help me!!!!!!!

Maurinko [17]

Answer:

165°

Step-by-step explanation:

x+15=180

4 0

2 years ago

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The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

No links, downloads, or anything of the sort. I will give brainliest!!!

TiliK225 [7]

Answer:

The answer is D

Step-by-step explanation:

5 0

3 years ago

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