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aleksklad [387]

3 years ago

9

21. Whether or not a scientists hypothesis is supported or contradicted, the scientists still has to explain what exactly happen

ed in an experiment when this situation occurs the
scientist is described as being

a. untruthful
b. pseudo
c objective
d. horrible

1 answer:

zheka24 [161]3 years ago

7 0

Objective (c).
scientist’s opinions don’t affect their presentation of facts.

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In a classical carnival ride, patrons stand against the wall in a cylindrically shaped room. Once the room gets spinning fast en

g100num [7]

Answer:

- the speed of a person "stuck" to the wall is 14.8 m/s

- the normal force of the wall on a rider of m=54kg is 1851 N

- the minimum coefficient of friction needed between the wall and the person is 0.29

Explanation:

Given information:

the radius of the cylindrical room, R = 6.4 m

the room spin with frequency, ω = 22.1 rev/minutes = 22.1 $\frac{2\pi }{60}$ = 2.31 rad/s

mass of rider, m = 54 kg

the speed of a person "stuck" to the wall

v = ω R

= 2.31 x 6.4

= 14.8 m/s

the normal force of the wall on a rider

F = m a

a = ω^2 R

= $\frac{v^{2} }{R^{2} }$ R

= $\frac{v^{2} }{R}$

F = $\frac{mv^{2} }{R}$

= $\frac{(54)(14.8)^{2} }{6.4}$

= 1851 N

the minimum coefficient of friction needed between the wall and the person

F(friction) = μ N

W = μ N

m g = μ $\frac{mv^{2} }{R}$

g = μ $\frac{v^{2} }{R}$

μ = $\frac{gR}{v^{2} }$

= $\frac{(9.8) (6.4)}{14.8^{2} }$

= 0.29

5 0

3 years ago

A cat lifting a barbell of 2.5 kg a distance of 3 meters. How much work is done lifting the barbell? How much work is done if th

Degger [83]

Work = (force) x (distance)

Force = weight of the barbell = (mass) x (gravity) = (2.5 kg) x (9.8 m/s²)

Work = (2.5 x 9.8 newtons) x (3 meters) = 74 newton-meters = 74 joules.

It takes 74 joules to lift the 2.5-kg load 3 meters up off the floor.

After that, as long as the load is held motionless, no more work is done.

7 0

3 years ago

levacccp [35]

Answer:

3.82746e+26 watts

Explanation:

There are two ways to solve this problem. One way is to use the equation

L = 4πσR²T⁴

where

L = the sun's bolometric (all-spectrum) luminous power

σ = 5.670374419e-8 W m⁻² K⁻⁴ = the Stefan-Boltzmann constant

R = 6.957e+8 meters = the sun's radius

T = 5771.8 K = the sun's effective temperature

You find that

L = 3.82746e+26 watts

The other way to solve the problem is to use the Planck integral for radiant flux.

L = 4π²R ∫(v₁,v₂) 2hv³/{c² exp[hv/(kT)]−1} dv

where

h = 6.62607015e-34 J sec

c = 299792458 m sec⁻¹

k = 1.380649e-23 J K⁻¹

v₁ = 0 = frequency band lower bound, in Hz

v₂ = ∞ = frequency band upper bound, in Hz

You find, once again, that

L = 3.82746e+26 watts

The advantage of using the Planck integral becomes clear when you want to calculate the sun's luminous power only in a specific band, rather than across the entire spectrum. For example, if we do the calculation again, except that we use

v₁ = 4.1e+14 = frequency band lower bound, in Hz

v₂ = 7.7e+14 Hz = frequency band upper bound, in Hz

restricting ourselves to the visible spectrum. We find that

L (visible) = 1.56799e+26 watts

So the fraction of the sun's luminosity that is in the visible spectrum is

L (visible) / L = 0.4096686

5 0

4 years ago

How do you measure the amplitude of a longitudinal wave?

sp2606 [1]

You do it by the pressure difference it causes in the medium. Even in transversal waves, you usually need different units than meters because the wave has electric and magnetic vectors and not really any height to speak of.

you measure the amount of excursion from the equilibrium (no wave) level of whatever parameter is fluctuating.

3 0

4 years ago

What everyday things exist bc of science?

fredd [130]

Paper..pencils...tables, walls...everything that is man made science played a huge factor in it because the first science was when some hairy dude was like i wonder what happens when i do this...same thing with food and drinks..how do you think milk was made..some dude was like hmmm..i wonder..and i think you can figure out the rest..hope i helped

6 0

3 years ago