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bija089 [108]
3 years ago
11

Present value lets us compare dollar values from different time periods.

Chemistry
1 answer:
kramer3 years ago
5 0
True? Not sure what the question is
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Lithium, sodium and potassium all belong to the same group of the periodic table.
Lady_Fox [76]

Answer:

Yes they are found in same period

4 0
3 years ago
Read 2 more answers
An object is found to have a mass of 54.3 g. Find the object’s density, if its volume is 47.18 cm3
Schach [20]

Answer:

d≈ 1.15 g/cm^3

Explanation:

The density of an object can be found by dividing the mass over the volume.

d= m/v

The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.

m= 54.3 g

v= 47.18 cm^3

Substitute the values into the formula.

d= 54.3 g/ 47.18 cm

Divide.

d= 1.150911403136922 g/cm^3

Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.

d ≈ 1.15 g/cm^3

The density is about 1.15 grams per cubic centimeter.

8 0
3 years ago
Of the following, which is most likely to result after a farmer sprays his crops with pesticides?
Anastasy [175]
Of the following, which is most likely to result after a farmer sprays his crops with pesticides?D. A neighbor’s well tests positive for pesticides. 

Carbon dioxide is a colorless, odorless gas. Why is it considered a pollutant? 
A. It gets into natural waters and kills fish.
6 0
4 years ago
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What is the simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens?
butalik [34]

The simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.

Sucrose is a diasaccharide having the formula; C12H22O11.

This implies that there are twenty two atoms of hydrogen and eleven atoms of oxygen in a molecule of sucrose.

This gives a ratio of 2 hydrogen atoms to one oxygen atom. Therefore, the simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.

Learn more: brainly.com/question/11347582

8 0
3 years ago
Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2
Elena L [17]

Mass of carbon monoxide : 0.95 g

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂

MW Fe₂O₃ : 159,69 g/mol

mol Fe₂O₃ :

\tt \dfrac{1.8}{159.69}=0.0113

mol ratio Fe₂O₃ : CO = 1 : 3, so mol CO :

\tt 3\times 0.0113=0.0339

mass CO (MW =  28,01 g/mol) :

\tt m=mol\times MW\\\\m=0.0339\times 28.01\\\\m=0.950~g

4 0
3 years ago
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