Balancing the equation, we get:
2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O
So
α = 2
β = 1
γ = 2
δ = 2
Answer:
Explanation:
The algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.
In order to know the formula of the negative Sulfur ion in pyrite, we must determine its oxidation state.
Let us make the make the oxidation number of sulfur = x
Therefore, FeS₂:
+2 +2x = 0
+2 = -2x
x = -1
The formula of the negative ion is S⁻
Eu2+ is stable because of the two electrons in its outermost orbit and after losing 4 electrons. Ce +4 is stable
What are lanthanide ions?
All lanthanide elements form trivalent cations, Ln3+, whose chemistry is largely determined by the ionic radius, which decreases steadily from lanthanum to lutetium. These elements are called lanthanides because the elements in the series are chemically similar to lanthanum.
The Ce metal has the following electronic configuration: [Xe] 4f¹5d¹6s²
It obtains noble gas configuration after losing 4 electrons. Ce +4 is stable, so.
Eu's electronic setup is as follows.
[Xe] 4 f ⁷6s²
[Xe] 4 f ⁷
Eu2+ is stable because of the two electrons in its outermost orbit. Additionally stable is its +3 oxidation state. Ce⁺²
To learn more about lanthanides click on the link below:
brainly.com/question/12756990
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In chemical equilibrium, radioactive decay occurs because of unstability due to the high neutron-to-proton ratio. Through time, the radioactive element is converted to a new element. This radioactive decay undergoes first order reaction. Its equation is in the form of
A = A₀e^(-kt), where A is the amount of the element after time t, A₀ is the original amount of element at t=0 and k is the rate constant.
Half-life is the amount of time for A to be 1/2 of A₀. Modifying the equation during half time, we let A=1/2 A₀. Then.
1/2 A₀ = A₀e^(-kt)
1/2 = e^(-k(5730))
k = 0.000121
Thus, the first-order rate constant is equal to 0.000121 per year.
Answer:
35.29%
Explanation:
% error = |experimental value - Accepted value| / Accepted Value x 100
Number of questions: 34
Number of questions answered: 22
%error = |22-34| / 34 x 100
Hence, John's percentage error is 35.29 % or 35.3%
