Explanation:
Since, the given reaction is as follows.
Initial: 36.1 atm 0 0
Change: 2x x x
Equilibrium: (36.1 - 2x) x x
Now, expression for 
of this reaction is as follows.
![K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%7B%5BNO%5D%5E%7B2%7D%7D)
As the initial pressure of NO is 36.1 atm. Hence, partial pressure of 
at equilibrium will be calculated as follows.
x = 18.1 atm
Thus, we can conclude that partial pressure of at equilibrium is 18.1 atm.
One atmosphere is equal to 101.3 kilopascals, the measurement of force that the atmosphere exerts at sea level. To convert 112 atmospheres to kilopascals, simply multiply the two together.
112 atm x (101.3 kPa/1 atm) = 11,345.6 kPa
/\
conversion factor
112 atmospheres is the same amount of pressure as 11,345.6 kilopascals.
1 molecule of NH3 has 3 atoms of H.
6.90*10²⁴ molecules NH3 have 3*6.90*10²⁴ =20.7*10²⁴ atoms H=2.07*10²⁵ atoms H
1 molecule H2O of has 2 atoms of H.
2.60*10²⁵ molecules of H2O have 2*2.60*10²⁵ =5.20 *10²⁵ atoms of H
2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.
Answer:
No
Explanation:
The answer would be no.
<em>Solid aluminium oxide cannot react with hydrogen gas to produce molten aluminium and water due to the fact that, on one hand, hydrogen as an element is not a strong enough reducing agent that can remove oxygen from the aluminium oxide. On the other hand, aluminium is more reactive than hydrogen and hence, cannot be displaced by hydrogen in solution.</em>
