The answer would be 425.599 because 1 ATM is 760 mmHg.
Answer:
800 degrees C g, I found this answer by using the formula to find how much energy was need to melt the ice. First you figure out the temperature change of ur ice (starting temp and ur final temp), and then you times that with the mass of the water.
Answer:
Boiling point of the solution is 100.78°C
Explanation:
This is about colligative properties.
First of all, we need to calculate molality from the freezing point depression.
ΔT = Kf . m . i
As the solute is nonelectrolyte, i = 1
0°C - (-2.79°C) = 1.86 °C/m . m . 1
2.79°C / 1.86 m/°C = 1.5 m
Now, we go to the boiling point elevation
ΔT = Kb . m . i
Final T° - 100°C = 0.52 °C/m . 1.5m . 1
Final T° = 0.52 °C/m . 1.5m . 1 + 100°C → 100.78°C
Nonmetals have the ability to attract electrons better than metals because they have a higher electron affinity or electronegativity than metals.
<h3>What is electronegativity?</h3>
Electronegativity is the tendency, or a measure of the ability, of an atom or molecule to attract electrons and thus form bonds.
An element in the periodic table with a high electronegativity will automatically have a high electron affinity.
Metals (low electronegativity) are known to lose electrons to non-metals (high electronegativity), hence, nonmetals have the ability to attract electrons better than metals because they have a higher electron affinity or electronegativity than metals.
Learn more about electronegativity at: brainly.com/question/2060520
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a) First, to get ΔG°rxn we have to use this formula when:
ΔG° = - RT ㏑ K
when ΔG° is Gibbs free energy
and R is the constant = 8.314 J/mol K
and T is the temperature in Kelvin = 25 °C+ 273 = 298 K
and when K = 4.4 x 10^-2
so, by substitution:
ΔG°= - 8.314 * 298 *㏑(4.4 x 10^-2)
= -7739 J = -7.7 KJ
b) then, to get E° cell for a redox reaction we have to use this formula:
ΔE° Cell = (RT / nF) ㏑K
when R is a constant = 8.314 J/molK
and T is the temperature in Kelvin = 25°C + 273 = 298 K
and n = no.of moles of e- from the balanced redox reaction= 3
and F is Faraday constant = 96485 C/mol
and K = 4.4 x 10^-2
so, by substitution:
∴ ΔE° cell = (8.314 * 298 / 3* 96485) *㏑(4.4 x 10^-2)
= - 2.7 x 10^-2 V
