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mel-nik [20]
3 years ago
15

HURRY! Carbon and oxygen combine to form carbon dioxide. What are the products, or what is the product, in this chemical reactio

n?
-carbon and oxygen
-carbon dioxide
-carbon only
-oxygen only
Chemistry
2 answers:
omeli [17]3 years ago
7 0
Carbon dioxide I’m pretty sure
Wittaler [7]3 years ago
5 0

Answer:

Carbon dioxide.

Explanation:

Hope this will help

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Why do we use balanced equations ?
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In a coffee-cup calorimeter, 150.0 mL of 0.50 M HCl is added to 50.0 mL of 1.00 M NaOH to make 200.0 g solution at an initial te
Zigmanuir [339]

Answer:

51.54°C the final temperature of the calorimeter contents.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl,\Delta H=-56 kJ/mol

moles=Molarity\times Volume (L)

Molarity of HCl= 0.50 M

Volume of HCl= 150.0 mL = 0.150 L

Moles of HCl= n

n=0.50 M\times 0.150 L=0.075 mol

Molarity of NaOH= 1.00 M

Volume of NaOH= 50.0 mL = 0.050 L

Moles of NaOH= n'

n'=1.00 M\times 0.050 L=0.050 mol

Since moles of NaOH are less than than moles of HCl. so energy release will be for neutralization of 0.050 moles of naOH by 0.050 moles of HCl.

n = 0.050

-56 kJ/mol=-\frac{Q}{n}

Q=56 kJ/mol\times 0.050 kJ/mol=2.8 kJ=2800 J

(1 kJ= 1000 J)

The energy change released during the reaction = 2800 J

Volume of solution = 150.0 mL + 50.0 mL = 200.0 mL

Density of the solution (water) = 1.00g/mL

Mass of the solution , m= 200 mL × 1.00 g/mL = 200 g

Now , calculate the final temperature by the solution from :

q=mc\times (T_{final}-T_{initial})

where,

q = heat gained = 2800 J

c = specific heat of solution = 4.184 J/^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 48.2^oC

Now put all the given values in the above formula, we get:

2800 J=200.0 g\times 4.184 J/^oC\times (T_{final}-48.2)^oC

T_{final}= 51.54^oC

51.54°C the final temperature of the calorimeter contents.

7 0
3 years ago
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