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3 years ago

A rectangle's width is 23 cm and its length is 9cm. what is its area

Mathematics

2 answers:

ANTONII [103]3 years ago

8 0

Width = 23cm, length = 9cm

A rectangle's Area = Length * width

Area = 9 cm * 23 cm = 207 cm²

Area = 207 cm²

myrzilka [38]3 years ago

4 0

$width =23 cm\\ length = 9cm \\ \\ \boxed{Area= w \cdot l} \\ \\ Area=23 \cdot 9 \\ \\ Area=207 \ cm^2$

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PLEASE HELP! I WILL GIVE BRAINLIEST ANSWER!

Aleks [24]

Answer:

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Step-by-step explanation:

Just calculate the amount of juice the bottle:

6 x pi x 8 x 3/4

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And then you can easiely count the number of bottles

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3 years ago

Death valley, California, has the lowest elevation in the united states.its elevation is 282 feet below sea level. Mount Mckinle

xxTIMURxx [149]

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6 0

4 years ago

Read 2 more answers

V2=u2+2as v 2 = u 2 + 2 a s Where v v is the final velocity (in m/s), u u is the initial velocity (in m/s), a a is the accelerat

allsm [11]

Answer:

<em>Final velocity, v = 21.75 m/s</em>

Step-by-step explanation:

Given that the relation between final velocity, initial velocity, acceleration and distance traveled is expressed as:

$v^2=u^2+2as$

Also, given that:

Initial velocity, u = 9 m/s

Acceleration, a = 7 m/ $s^2$

Distance, s = 28 m

To find:

Final velocity, v = ?

Solution:

The given relation between v, u, a and s is:

$v^2=u^2+2as$

We have the values of initial velocity, acceleration and distance traveled in the question statement. We just need to put all these values to find the value of final velocity.

Let us put all the values in the given equation and try to find final velocity, v:

$v^2=9^2+2\times 7 \times 28\\\Rightarrow v^2=81+14 \times 28\\\Rightarrow v^2=81+392\\\Rightarrow v^2=473\\\Rightarrow v=\sqrt{473}\\\Rightarrow v=21.75\ m/s$

So, the answer is:

<em>final velocity, v = 21.75 m/s</em>

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3 years ago

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VMariaS [17]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

For a craft activity at a day care, each child will need 1.75 yards of ribbon and 2.8 yards of fabric. There are 25 yards of rib

Kamila [148]

Total number of yards of ribbon available = 25 yards.

Number of yards of fabric available = 30 yards.

Number of yards of ribbon a child need = 1.75 yards

Number of yards of fabric a child need = 2.8 yards.

<em>Total number of children participate in the activity for 25 yards of ribbon = 25/1.75 = 14.28 approximately 15 children.</em>

<em>Total number of children participate in the activity for 30 yards of fabric = 30/2.8 = 10.7 approximately 11 children.</em>

<h3>Therefore, maximum 11 children can participate in the activity because each child required both 1.75 yards of ribbon and 2.8 yards of fabric .</h3>

7 0

4 years ago