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3 years ago

When there is an increase in temperature of a gas in an

Chemistry

1 answer:

Ahat [919]3 years ago

3 0

Answer:increase In kinetic energy of molecules

Explanation:increase in kinetic energy of molecules

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What type of allele masks the expression of the recessive allele?

aniked [119]

The Dominant trait or allele masks the recessive because it is dominant. an easy way to remember this is how the lead wolf (dominant alleles) shows it's dominance over the rest of the pack (the recessive alleles)

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4 years ago

The density of gold is 19.3 g/cm3. What is the volume of a 575 gram bar of pure gold?

Gnoma [55]

Answer:

The answer to your question is: Volume = 29.79 cm³

Explanation:

Data

Density of gold = 19.3 g/cm3

Mass = 575 grams

Formula

density = mass / volume

Volume = mass/density

Volume = 575 g / 19.3 g/cm3

Volume = 29.79 cm³

3 0

4 years ago

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The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr

jenyasd209 [6]

Answer : The final temperature of the water is, $22.5166^oC$

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

$\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole$

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

$2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ$

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives $\frac{6542 kJ}{2}\times 0.1103=360.7913kJ$ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : $q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})$

where,

$q_w$ = heat released = 360.7913 kJ = 36079.13 J

$m_w$ = mass of water = 5691 g

$c_w$ = specific heat of water= $4.18J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $21^oC$

Now put all the given values in the above formula, we get:

$36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)$

$T_{final}=22.5166^oC$

Therefore, the final temperature of the water is, $22.5166^oC$

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4 years ago

Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration on nitrate, [NO3^-], is 0.10 M. What

VikaD [51]

Answer:

The concentration of nitrate ion $NO_{3}^{-}$ is 0.033 M.

Explanation:

$Al(NO_{3})_{3} \rightarrow Al^{3+} + NO_{3}^{-}$

1 mole of $[Al^{3+}]$ = 3 mole $NO_{3}^{-}$

Let $[NO_{3}^{-}]$ = 3y

then according to above reaction,

$[Al^{3+}]$ = y

$[NO_{3}^{-}]$ = 0.10 M (given)

$[Al^{3+}]$ = ?

3y = 0.10 M

$y = \frac{0.1}{3}$

y = 0.033 M

So ,concentration of $[Al^{3+}]$ = y = 0.033 M

5 0

3 years ago

Which of the following is an example of non-matter?

Lera25 [3.4K]

stay safe and have a great day<8

4 0

3 years ago

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