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3 years ago

Endoplasmic reticulum is found in the cells of

Chemistry

2 answers:

vovangra [49]3 years ago

6 0

Endoplasmic reticulum is an organelle found in both eukaryotic animal and plant cells.

hichkok12 [17]3 years ago

6 0

Endoplasmic reticulum is an organelle found in both eukaryotic animal and plant cells. It often appears as two interconnected sub-compartments, namely rough ER and smooth ER. Both types consist of membrane enclosed, interconnected flattened tubes

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A compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. what is the empirical formula for this compound?

kodGreya [7K]

Let the total mass of the compound is 100 g.

Mass of N = 63.65 % = 63.65 g

Mass of O = 36.35 % = 36.35 g

Molar mass of N = 14.01 g/mol

Molar mass of O = 16.00 g/mol

Number of moles (mol) = mass (g) / molar mass(g/mol)

Number of Moles of N = 63.65 g / 14.01 g/mol = 4.54 mol

Number of Moles of O = 36.35 g / 16.00 g/mol = 2.27 mol

Divide the Number of moles of each element with the lowest number of moles, here lowest number of moles is 2.27 .

Dividing number of the moles of each element by lowest number of moles to get the mole ratio between elements.

N = 4.54 mol / 2.27 mol = 2

O = 2.27 mol / 2.27 mol = 1

So, Empirical formula = N₂O₁ = N₂O

8 0

4 years ago

Read 2 more answers

Right now I’m a freshmen, and we got our scheduling paper for next year as sophomores. I’m wondering if I should take chemistry

Anastasy [175]

Anatomy I think it's important to know anatomy as a young adult so u are self aware of your body

3 0

3 years ago

Read 2 more answers

If 0.500 L of a 4.00-M solution of copper nitrate, Cu(NO3)2, is diluted to a volume of 1.50 L by the addition of water, what is

Wewaii [24]

Answer:

1.33 M

Explanation:

We'll begin by writing out the data obtained from the question. This includes the following:

Volume of the stock solution (V1) = 0.5L

Molarity of the stock solution (M1) = 4M

Volume of diluted solution (V2) = 1.5L

Molarity of the diluted solution (M2) =.?

With the application of the dilution formula, the molarity of the diluted solution can be obtained as follow:

M1V1 = M2V2

4 x 0.5 = M2 x 1.5

Divide both side by 1.5

M2 = (4 x 0.5) / 1.5

M2 = 1.33 M

Therefore the molarity of the diluted solution is 1.33 M

8 0

3 years ago

Uranium-232 has a half-life of 68.8 years. After 344.0 years, how much uranium-232 will remain from a 100.0-g sample?

amm1812

Answer: 3.13 g

Explanation:

Radioactive decay follows first order kinetics.

Half-life of uranium-232 = 68.8 years

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{68.8}= 0.010072674 year^{-1}$

$N=N_o\times e^{-\lambda t}$

N = amount left after time t

$N_0$ = initial amount

$\lambda$ = rate constant

t= time

$N_0$ = 100 g, t= 344 years, $\lambda=0.010072674 years^{-1}$

$N=100\times e^{- 0.010072674 years^{-1}\times 344 years}$

N=3.13g

8 0

3 years ago

Read 2 more answers

What quantity of potassium phosphate, in grams, is required to prepare 500.0 ml of solution where you the concentration of potas

Readme [11.4K]

Answer: 3.54

Explanation:

You're forgetting to divide by 3 for the 3 moles of potassium that are in potassium phosphate.

Potassium Phosphate= K3PO4

3 0

3 years ago