Choose the best graph that represents the linear equation: -2y = x + 6

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

Answer:

graph A

Step-by-step explanation:

it goes through -6 and -3

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A CD player is on sale for $90 at an electronics store. If the original price was $125, what was the percent of discount

krek1111 [17]

This is the working of how it is 28% discount

Find the amount of discount : $125 - $90 = $35
Divide by the original price : $35/125 = 0.28
Change in to percentage : 0.28 x 100 = 28%

Therefore the percentage discount is 28% off

:)

8 0

3 years ago

F(x) = lnx/x

My name is Ann [436]

$f(x) = \frac{lnx}{x}$

(a) $f'(x) = \frac{d}{dx}[\frac{lnx}{x}]$
Using the quotient rule:
$f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}$
$f'(x) = \frac{1 - lnx}{x^{2}}$

For maximum, f'(x) = 0;
$\frac{1 - lnx}{x} = 0$
$lnx = 1, x = e$

(b) <em>Deduce:
</em> $e^{x} \geq x^{e}, x > 0$
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
$\frac{ln(e)}{e} \geq \frac{lnx}{x}$
$\frac{1}{e} \geq \frac{lnx}{x}$ , since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
$\frac{x}{e} \geq lnx$
$x \geq elnx$
$x \geq ln(x^{e})$

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
$e^{x} \geq e^{ln(x^{e}})$
$e^{x} \geq x^{e}$ , as required.