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katrin2010 [14]
2 years ago
11

Which statement describes why sodium reacts more vigorously than magnesium to hydrochloric acid? Refer to the periodic table. Ci

rcle the letter of the correct answer.
1) Sodium has a smaller atomic radius than magnesium.
2)Sodium has a lower ionization energy than magnesium.
3)Magnesium has a lower ionization energy than sodium.
Chemistry
2 answers:
lions [1.4K]2 years ago
8 0

Sodium has a lower ionization energy than magnesium describes why sodium reacts vigorously than magnesium chloride.

<h3>Why is sodium more reactive than magnesium?</h3>
  • Sodium is more reactive than magnesium because it has the ability to easily lose electron, hence have lower ionization energy.
  • Sodium belong to group one on the periodic table and they are called akali metal while magnesium belong to group two on the periodic table and they are called alkali Earth metal.

  • Sodium and magnesium belong to the in the 3rd period. Iin the outermost energy level sodium has one electron but magnesium has 2 electrons. Therefore, there is more attraction abetween the nucleus and electrons in magnesium than that of sodium.

Therefore, sodium is more reactive than magnesium chloride because of lower ionization energy.

For more details on sodium reactivity, check the link below.

brainly.com/question/6837593

ivolga24 [154]2 years ago
4 0

Answer:

Its B all the others arent true and also dont make any sense

Explanation:

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Calcium cyanamide, CaCN2, reacts with water to form calcium carbonate and ammonia. CaCN2(s)+3H2O(l)→CaCO3(s)+2NH3(g). How many g
Norma-Jean [14]

298 g of calcium carbonate CaCO₃

Explanation:

We have the following chemical reaction:

CaCN₂ (s) + 3 H₂O (l) → CaCO₃ (s)+ 2 NH₃ (g)

number of moles = mass / molar weight

number of moles of H₂O = 161 / 18 = 8.94 moles

Knowing the chemical reaction we devise the following reasoning:

if        3 moles of H₂O produces 1 mole of CaCO₃

then  8.94 moles of H₂O produces X moles of CaCO₃

X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃

mass =  number of moles × molar weight

mass of CaCO₃ = 2.98 × 100 = 298 g

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number of moles

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You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acetate plus acetate concentration
vovangra [49]

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Given:

Acetic Acid/Sodium Acetate buffer of pH = 5.0

Let HA = acetic acid

A- = sodium acetate

Total concentration [HA] + [A-] = 250 mM ------(1)

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Based on Henderson-Hasselbalch equation

pH = pKa + log[A-]/[HA]

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[A-] = 1.77[HA] -----(2)

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[A-] = 1.77(90.25) = 159.74 mM



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