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Sergeeva-Olga [200]
3 years ago
9

A dilation with a scale factor of 3.5 and centered at the origin is applied to PQ¯¯¯¯¯ with endpoints P(2, 5) and Q(2, 1).

Mathematics
2 answers:
pshichka [43]3 years ago
5 0
The answer for p is (7,17.5)
Q is (7,3.5) I have the same test
Otrada [13]3 years ago
3 0

Answer: The answer is P'(7, 17.5) and Q'(7, 3.5).

Step-by-step explanation:  Given that a line segment PQ is dilated with a scale factor of 3.5 where origin is the centre of dilation.

The end points of segment PQ are P(2, 5) and Q(2, 1).

Therefore, after dilation, the coordinates of the end points become

P'=(2\times 3.5,5\times 3.5)=(7, 17.5),\\\\Q'=(2\times 3.5,1\times 3.5)=(7,3.5).

Thus, the coordinates of P' are (7, 17.5) and the co-ordinates of Q' are (7, 3.5).

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-11-7= please help me
Oxana [17]
The answer would be -18. Hope this helps!
6 0
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Part A: What is the y-intercept of the function, and what does this tell you about the car?
jeyben [28]
There's an x and y intercept the y is how tall the car is
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3 years ago
A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(
ratelena [41]

Answer:

The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is -80 feet per second.

Step-by-step explanation:

The function that models the height of the ball is:

f(t)=-16t^2+48t=160

At t=3, f(3)=-16(3)^2+48(3)+160=160

At t=5, f(5)=-16(5)^2+48(5)+160=0

The average rate of change is simply the slope of the secant line connecting.

(3,f(3)) and (5,f(5)).

The average rate of change

=\frac{f(3)-f(5)}{3-5}

=\frac{160-0}{-2}

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5 0
4 years ago
Find the range of each function for the domain {-4, -2, 0, 1.5, 4}. f(x) = 5x^2 + 4
andrew11 [14]
Substitute x with the members of the domain.
f(x) = 5x² + 4

Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84

Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24

Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4

Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25

Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84

The range of the function for those domain is {4, 24, 15.25, 84}
4 0
3 years ago
An is the way to show which term in the sequence you want.<br><br>True <br>False​
kari74 [83]
True the n is usually where the number would go like the a100th term 100 would be n :)
5 0
3 years ago
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